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victus00 [196]
2 years ago
14

I NEED HELP PLEASE VERY URGENT

Mathematics
2 answers:
vagabundo [1.1K]2 years ago
5 0
X= 39
Y= 69

When you plug these variables in each equation - the equation is true.
I am Lyosha [343]2 years ago
4 0
(X,Y)=(39,69) is the answer
You might be interested in
3/12 and 5/x are<br> equivalent ratios. Solve for<br> X. Pls help asap
Phoenix [80]

Answer:

3/12  and 5/x

12 times 5 is 60 so 3 times 20 shall be 60

3/12 = 5/20

:)

4 0
3 years ago
The perimeter of the triangle below is 97 cm.
Sloan [31]

Answer:

The length of EF = x = 18 cm

Option A is correct.

Step-by-step explanation:

Ware given perimeter of triangle = 97 cm

We need to find length of EF = x = ?

The length of EG = x+7

The length of EF = x

The length of GF = 3x

The formula used is: Periemter \ of \ triangle= Sum \ of \ all \ sides \ of \ triangle

Putting values and finding x i.e length of EF

Periemter \ of \ triangle= Sum \ of \ all \ sides \ of \ triangle\\97=x+7+x+3x\\97-7=5x\\5x=90\\x=\frac{90}{5}\\x=18 \ cm

So, value of x=18 cm

The length of EF = x = 18 cm

Option A is correct.

4 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!
Paraphin [41]

the overhead, fixed costs, is $1000.

the variable cost is $200, so if she sells "x" tiles, then her costs is 200*x or 200x.

total costs then will just be C(x) = 200x + 1000.

namely both costs added together.

Revenue is just how much it's been taken in from the sales, since each tile is selling for $240, then the revenue is simply 240*x or just R(x) = 240x.

break even point is when those two guys equal each other

\bf \stackrel{R(x)}{240x}=\stackrel{C(x)}{200x+1000}\implies 40x=1000\implies x=\cfrac{1000}{40}\implies x=25

what if the cost for each tile were $220, 20 bucks more?

\bf \stackrel{R(x)}{240x}=\stackrel{C(x)}{220x+1000}\implies 20x=1000\implies x=\cfrac{1000}{20}\implies x=50

well, if the cost for each tile is $200, her break-even point is at 25 units, namely once she has sold 25 tiles, she's has lost nothing, has won nothing either, but hasn't lost anything.

if the cost is however $220 instead, her break-even point comes much later, at 50 units, so she'll have to sell more tiles in order to not have any losses, so she's worse off if the cost is more or course.

4 0
3 years ago
Help me get the answer
drek231 [11]
This is hard- DHJDHSJS
3 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
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