A car moving along a straight highway it at speed of 144 km/h is brought to a within a distance of 200m..

A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an obser

madam [21]

Answer:

the speed of the cruiser relative to the pursuit ship is 0.3846c

Explanation:

the solution is in the attached Word file

Download docx

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3 years ago

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The Earth's diameter at the poles is _____.

maria [59]

Less than it’s diameter at the equator

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3 years ago

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You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f

ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

Finding the velocity the corn was moving at from $s=vt+0.5at^{2}$

where s = length of stick, t = time, a = acceleration due to gravity

$s=vt+0.5at^{2}$

1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

1 = 0.121v + 0.0717

1 - 0.0717 = 0.121v

v = 7.67 m/s

Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

v = final velocity = 7.67 m/s

u = initial velocity = 0 m/s since it was initially at rest

a = acceleration due to gravity

t' = time taken to fall to the top of the stick

7.67 = 0 + (9.8 x t')

t' = 7.67 / 9.8 = 0.78 s

using the time above to find the distance between the branch the corn falls from and the top of the stick using $s=vt+0.5at^{2}$ where:

s = distance

v = initial velocity = 0 m/s since it was initially at rest

t = time = 0.78 s

a = acceleration due to gravity = 9.8

s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

s = 2.98 m

Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

2.98 + 2.07 = 5.05 m

5 0

3 years ago

If a force of 12 N is applied to an object with a mass of 2 kg, what will be its acceleration? 0.17 m/s2 6 m/s2 24 m/s2 14 m/s2

Arturiano [62]

Answer

Correct Answer is

6 m/s^2

Explanation

in this question we have given

Force=12N

mass of oject=2kg

we know that

force= mass* acceleration

therefore,

acceleration=Force/mass.............(1)

Put values of mass and force in equation 1

$acceleration = 12/2\\\\acceleration=6m/s^2\\$

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3 years ago

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A certain heat engine takes in 300 J of energy from a hot source and then transfers 200 J of that energy to a colder object. Wha

Greeley [361]

Answer:

The efficiency is 0.33, or 33%.

Explanation:

From the thermodynamics equations, we know that the formula for the efficiency of a heat engine is:

$\eta=1-\frac{Q_2}{Q_1}$

Where η is the efficiency of the engine, Q_1 is the heat energy taken from the hot source and Q_2 is the heat energy given to the cold object. So, plugging the given values in the formula, we obtain:

$\eta=1-\frac{200J}{300J}=0.33$

This means that the efficiency of the heat engine is 0.33, or 33% (The efficiency of an engine is dimensionless).

5 0

3 years ago