1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kirill [66]
3 years ago
12

Why is it important that radioisotopes used in diagnostic tests have short half-lives? 20 A) These radioisotopes have a greater

activity so they B) This minimizes the harmful side effects of the radiation. C) This is necessary so the radioisotopes will have high energy D) These radioisotopes are less expensive. E) These radioisotopes are more abundant in nature are easier to monitor
Physics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

Option B) This minimizes the harmful side effects of the radiations

Explanation:

Half-life is the time taken for the decay of an radio-active atom in which it disintegrates such that it becomes half of its value at the beginning.... The nuclei should be in active mode for a longer duration sufficient for the treatment of the condition but these nuclei should have a sufficient  shorter half life so that they don't get enough time to cause any  damage to the health of the person other than treating the cause.

A shorter half life gives the assurance that the radiation after the treatment will leave the body without getting accumulated and cause harm to the body cells and other organs.

You might be interested in
A mixture of helium and argon gas is expanded from a volume of 29.0L to a volume of 82.0L, while the pressure is held constant a
finlep [7]

Answer:

322 kJ

Explanation:

The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.

When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.

For a constant pressure, the work can be calcutated by:

W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:

p = 60 atm = 6.08x10⁶ Pa

ΔV = 82.0 - 29.0 = 53 L = 0.053 m³

W = 6.08x10⁶x0.053

W = 322x10³ J

W = 322 kJ

8 0
3 years ago
PLEASE I NEED HELP WITH 6 and 8 !!!! I will love u sm
likoan [24]

Answer:

Explanation:

006

They are acting in opposite directions. Therefore the net force is found by subtraction. The sign is the same as the larger number.

Net Force = 99.6 - 52.8 = 46.8 N acting in the same direction as the 99.6  which is upward.

008

If the two forces act in the same direction, the net force is found by addition.

Net Force = 99.6 + 52.8  = 152.4 N downward.

4 0
3 years ago
Read 2 more answers
A scuba diver and her gear displace a volume of 68.5 L and have a total mass of 71.8 kg . Part A What is the buoyant force on th
Luba_88 [7]

Answer:

A) Fb = 671.3 N

B) The diver will sink.

Explanation:

A)

The buoyant force applied on an object by a fluid is given by the following formula:

Fb = Vρg

where,

Fb = Buoyant Force = ?

V = Volume of the water displaced by the object = 68.5 L = 0.0685 m³

ρ = Density of Water = 1000 kg/m³

g = 9.8 m/s²

Therefore,

Fb = (0.0685 m³)(1000 kg/m³)(9.8 m/s²)

<u>Fb = 671.3 N</u>

B)

Now, in order to find out whether the diver sinks or float, we need to find weight of the diver with gear.

W = mg = (71.8 kg)(9.8 m/s²)

W = 703.64 N

Since, W > Fb. Therefore, the downward force of weight will make the diver sink.

<u>The diver will sink.</u>

8 0
3 years ago
A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren is 500 Hz
wariber [46]

Answer:

change in frequency is 636 Hz

Explanation:

given data

speed v1 = 36 m/s

speed v2 = 45 m/s

frequency f = 500 Hz

speed of sound s = 343 m/s

to find out

what is the change in frequency

solution

we know here change of frequency formula that is

frequency = \frac{s+v1}{s+v2} (f)   ...................1

put here value in equation 1

and we take v2 = -45 because opposite direction

frequency = \frac{s+v1}{s-v2} (f)

frequency = \frac{343+36}{343-45} (500)

frequency = 636

so change in frequency is 636 Hz

8 0
4 years ago
I need both parts please (a) Given a material with an attenuation coefficient (a) of 0.6/cm, what is the intensity of a beam (wi
Masteriza [31]

Answer:

<h3>a.</h3>
  • After it has traveled through 1 cm : I(1 \ cm) = 0.5488 I_0
  • After it has traveled through 2 cm : I(2 \ cm) = 0.3012 I_0
<h3>b.</h3>
  • After it has traveled through 1 cm : od( 1\ cm) =  0.2606
  • After it has traveled through 2 cm :  od( 2\ cm) =  0.5211

Explanation:

<h2>a.</h2>

For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient \mu the formula is:

I(x) = I_0 e^{-\mu x}

where I is the intensity of the beam, I_0 is the incident intensity and x is the length of the material traveled.

For our problem, after travelling 1 cm:

I(1 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 1 cm}

I(1 \ cm) = I_0 e^{- 0.6}

I(1 \ cm) = I_0 e^{- 0.6}

I(1 \ cm) = 0.5488 \ I_0

After travelling 2 cm:

I(2 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 2 cm}

I(2 \ cm) = I_0 e^{- 1.2}

I(2 \ cm) = I_0 e^{- 1.2}

I(2 \ cm) = 0.3012 \ I_0

<h2>b</h2>

The optical density od is given by:

od(x) = - log_{10} ( \frac{I(x)}{I_0} ).

So, after travelling 1 cm:

od( 1\ cm) = - log_{10} ( \frac{0.5488 \ I_0}{I_0} )

od( 1\ cm) = - log_{10} ( 0.5488 )

od( 1\ cm) = - (  - 0.2606)

od( 1\ cm) =  0.2606

After travelling 2 cm:

od( 2\ cm) = - log_{10} ( \frac{0.3012 \ I_0}{I_0} )

od( 2\ cm) = - log_{10} ( 0.3012 )

od( 2\ cm) = - (  - 0.5211)

od( 2\ cm) =  0.5211

3 0
3 years ago
Other questions:
  • The propeller of an airplane is 9 feet in diameter. What is the speed of the tip of a propeller blade if the angular velocity of
    10·2 answers
  • Questions 1 – 5 use the following word bank to place the correct letter in the space that correctly completes the sentence. A.PA
    15·1 answer
  • The phrase “20 m/s to the east” is an an example of
    9·2 answers
  • What city in North America starts with o and has six letters
    6·2 answers
  • Two stationary point charges of 3.00 nC and 2.00 nC are separated by a distance of 50.0 cm. An electron is released from rest at
    7·1 answer
  • Rank these significant figures numbers from the least to the most
    8·1 answer
  • If a driver has taken drugs the thinking distance will be increased. True or false. Why?
    11·2 answers
  • Object a with a mass of 1.5 kilograms is moving with a velocity of 11.2 meters/second (moving in the x direction). it has a perf
    8·2 answers
  • A woman on a bridge 84.5 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an a
    14·1 answer
  • A science teacher gives a student four beakers, each with a different liquid inside. The table provided shows the volume of each
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!