Answer:
26m/s²
Explanation:
Given parameters:
Mass of the student = 60kg
Weight = 1560N
Unknown:
Acceleration due to gravity = ?
Solution:
Weight is a force on a body due to gravity;
Weight = mass x gravity
Insert the given parameters and solve;
1560 = 60 x gravity
Gravity = = 26m/s²
Answer:
0.5m
Explanation:
v=f×lamda
v is 300m/s, f is 600Hz, lamda is ?
lamda=v/f
lamda=300/600
lamda =3/6=1/2m
The greater the change in velocity, or speed.
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
<u>Formula</u>
F = E×Q .......................... Equation 1
Where:
- F = Force on the charge
- E = Electric Field
- Q = charge
From the question,
Given:
Substitute these values into equation 1
Note: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
Learn more about Electric Field here: brainly.com/question/14015797
Answer:
3.528×10² V.
Explanation:
potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,
V = kq/r..................... Equation 1
And
E = kq/r² .................. Equation 2
Comparing equation 1 and equation 2,
V = E×r............................. Equation 3
Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.
Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.
Substitute into equation 3,
V = 6.3×10⁵×0.00056
V = 3.528×10² V.
Hence the potential difference of the plate = 3.528×10² V.