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Vedmedyk [2.9K]
2 years ago
5

I will give the Branliest!!! In which body of water can you see your reflected image better, a pond or an ocean? Why? (Please ex

plain correctly)
Physics
2 answers:
Rudiy272 years ago
7 0

Answer: Pond

Explanation: ponds form naturally and by the way theu contain less salt which has less density in the water, thus making it easy to see yourself in the pond

GREYUIT [131]2 years ago
4 0

Answer:

I would say a pond

Explanation:

A pond is more still than an ocean, therefore you could see your reflection better

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What is suvat in physics ?​
Crank

Answer:

suvat is an acronym of five variables that describe a system in motion. a, s, u, v and t

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2 years ago
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I will give brainliest) According to Newton's second law of motion, when an object is acted on by an unbalanced force, how will
evablogger [386]
Newton's<span> first </span>law of motion<span> has been frequently stated throughout this lesson. An</span>object<span> at rest stays at rest and an </span>object<span> in </span>motion<span> stays in </span>motion<span> with the same speed and in the same direction unless </span>acted<span> upon by an </span>unbalanced force<span>.</span>
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3 years ago
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1. Two students have volunteered to explore the galaxy in a
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Answer:a

Explanation:

I guess

7 0
3 years ago
If a high jumper needs to make his center of gravity rise 1.50 m, how fast must he be able to sprint? Assume all of his kinetic
sergiy2304 [10]

Answer:

v = 5.42 m/s

Explanation:

given,

height of the jumper = 1.5 m

velocity of sprinter = ?

kinetic energy can be transformed into potential energy

m g h = \dfrac{1}{2}mv^2

g h = \dfrac{1}{2}v^2

v =\sqrt{2gh}

v =\sqrt{2\times 9.8 \times 1.5}

v = 5.42 m/s

Speed of the sprinter is equal to v = 5.42 m/s

7 0
3 years ago
A 5 cm spring is suspended with a mass of 3.8589 g attached to it which extends the spring by 1.5747 cm. The same spring is plac
lana66690 [7]

Answer:

charges of the beads is 1.173 ×10^{-15} C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

extend spring x = 1.5747 cm = 0.15747 m

spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know  force for mass

force  = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

and

force for spring's extension

force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 ×10^{9} )

so charges of the beads = 1.173 ×10^{-15} C

3 0
2 years ago
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