Answer:
3
Step-by-step explanation:
divide the top number by the bottom to always find the constant of proportionality :D
Answer:
Jaylynn draws a hen with a scale of
2
22 units on her graph paper represents
6
cm
6cm6, space, c, m. The hen is
1
6
1616 units tall in the drawing.
A hen on graph paper. A 16-unit long line is labeled, "height." A 2-unit long scale is labeled, "6 centimeters."
6
cm
6 cmheight
What is the height, in
cm
cmc, m, of the actual hen?
Step-by-step explanation:
43-7= 36
Range is highest number minus smallest number
Answer:
1) ![E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%](https://tex.z-dn.net/?f=%20E%28M%29%20%3D%2014%2A0.3%20%2B%2010%2A0.4%20%2B%2019%2A0.3%20%3D%2013.9%20%5C%25)
2) ![E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%](https://tex.z-dn.net/?f=E%28J%29%3D%2022%2A0.3%20%2B%204%2A0.4%20%2B%2012%2A0.3%20%3D%2011.8%20%5C%25)
3) ![E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1](https://tex.z-dn.net/?f=%20E%28M%5E2%29%20%3D%2014%5E2%2A0.3%20%2B%2010%5E2%2A0.4%20%2B%2019%5E2%2A0.3%20%3D%20207.1%20)
And the variance would be given by:
![Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89](https://tex.z-dn.net/?f=Var%20%28M%29%3D%20E%28M%5E2%29%20-%5BE%28M%29%5D%5E2%20%3D%20207.1%20-%2813.9%5E2%29%3D%2013.89)
And the deviation would be:
4) ![E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8](https://tex.z-dn.net/?f=%20E%28J%5E2%29%20%3D%2022%5E2%2A0.3%20%2B%204%5E2%2A0.4%20%2B%2012%5E2%2A0.3%20%3D194.8%20)
And the variance would be given by:
![Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56](https://tex.z-dn.net/?f=Var%20%28J%29%3D%20E%28J%5E2%29%20-%5BE%28J%29%5D%5E2%20%3D%20194.8%20-%2811.8%5E2%29%3D%2055.56)
And the deviation would be:
Step-by-step explanation:
For this case we have the following distributions given:
Probability M J
0.3 14% 22%
0.4 10% 4%
0.3 19% 12%
Part 1
The expected value is given by this formula:
![E(X)=\sum_{i=1}^n X_i P(X_i)](https://tex.z-dn.net/?f=%20E%28X%29%3D%5Csum_%7Bi%3D1%7D%5En%20X_i%20P%28X_i%29)
And replacing we got:
![E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%](https://tex.z-dn.net/?f=%20E%28M%29%20%3D%2014%2A0.3%20%2B%2010%2A0.4%20%2B%2019%2A0.3%20%3D%2013.9%20%5C%25)
Part 2
![E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%](https://tex.z-dn.net/?f=E%28J%29%3D%2022%2A0.3%20%2B%204%2A0.4%20%2B%2012%2A0.3%20%3D%2011.8%20%5C%25)
Part 3
We can calculate the second moment first with the following formula:
![E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1](https://tex.z-dn.net/?f=%20E%28M%5E2%29%20%3D%2014%5E2%2A0.3%20%2B%2010%5E2%2A0.4%20%2B%2019%5E2%2A0.3%20%3D%20207.1%20)
And the variance would be given by:
![Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89](https://tex.z-dn.net/?f=Var%20%28M%29%3D%20E%28M%5E2%29%20-%5BE%28M%29%5D%5E2%20%3D%20207.1%20-%2813.9%5E2%29%3D%2013.89)
And the deviation would be:
Part 4
We can calculate the second moment first with the following formula:
![E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8](https://tex.z-dn.net/?f=%20E%28J%5E2%29%20%3D%2022%5E2%2A0.3%20%2B%204%5E2%2A0.4%20%2B%2012%5E2%2A0.3%20%3D194.8%20)
And the variance would be given by:
![Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56](https://tex.z-dn.net/?f=Var%20%28J%29%3D%20E%28J%5E2%29%20-%5BE%28J%29%5D%5E2%20%3D%20194.8%20-%2811.8%5E2%29%3D%2055.56)
And the deviation would be: