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galben [10]
2 years ago
6

. If the moon orbits Earth along the exact ecliptic (as the sun does): a. precession would not occur. b. days and nights would n

o longer be equal on the dates of the equinoxes. c. a total lunar and a total solar eclipse would occur every month. d. ocean tides would not occur.
Physics
1 answer:
Ostrovityanka [42]2 years ago
4 0

If the moon orbits Earth along the exact ecliptic a total lunar and solar eclipse would occur every month.

The answer is option C.

A solar eclipse happens when the Moon passes between the sun and Earth, casting a shadow on earth that either fully or partly blocks the sun's light in some areas. This most effective takes place every so often, due to the fact the Moon does not orbit inside the specific same plane because the solar and Earth do.

The moon's route crosses the ecliptic kind two times every month, and a solar eclipse takes place while the solar happens to be there at some point during the crossing. There's a terrific hazard of this approximately once each six months.

Learn more about the solar eclipse here: brainly.com/question/21576036

#SPJ4

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A train travelling at a speed of 108km/h.how much distance is it traveling every second ?
Nesterboy [21]
Hey there! 

To solve this question, lets convert 108 km/h into meters per second. 

1 km/h is equal to 0.277778 m/s

To convert 108 km/h into m/s, we just multiply 0.277778 by 108. 

0.277778 × 108 = 30.000024

So, the train is travelling at approximately 30 meters per second. 

Thank you!
3 0
4 years ago
What is the force of gravitational attraction between an object with a mass of 100 kg and another object that has a mass of 300
HACTEHA [7]

Answer:

5 x 10⁻⁷N

Explanation:

Given parameters:

Mass of object 1  = 100kg

Mass of object 2 = 300kg

Distance  = 2m

Unknown:

Force of gravitational attraction between the objects  = ?

Solution:

From Newton's law of universal gravitation we derive an expression:

        Fg  = \frac{G m_{1} m_{2}   }{r^{2} }

G is the universal gravitation constant = 6.67 x 10⁻¹¹

m is the mass

r is the distance between the bodies

 Now insert the parameters and solve;

     Fg  = 6.67 x 10⁻¹¹ x \frac{100 x 300}{2^{2} }   = 5 x 10⁻⁷N

3 0
3 years ago
An object is thrown upwards with a velocity of 3 meters per second, such that the only force acting on it is gravity (accelerati
3241004551 [841]

Answer:

Correct answer:  A.)  V = - 16.6 m/s down

Explanation:

Given:

V₀ = 3 m/s  initial velocity

t = 2 seconds

g = 9.8 m/s²

V(t) = V(2) = ?

The movement described is a vertical upward shot

For velocity at any time is valid the next formula

V = V₀ - g · t

V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down

Under condition that it has a enough drop height with respect to the ejection point.

God is with you!!!

3 0
4 years ago
Read 2 more answers
You raise a bucket of water from the bottom of a well that is 12 m deep. the mass of the bucket and the water is 5.00 kg, and it
MArishka [77]
Given: Mass m = 5.00 Kg;    Height h = 12 m;    Time t = 15 s

Required: Power P = ?

Formula: P = Fd/t  = mgh/t

               P = (5.0 Kg)(9.8 m/s²)(12 m)/15 s

               P = 39.2 Kg.m²/s²  or
 
               P = 39.2 J





4 0
3 years ago
What is the term used for the rate at which distance is traveled?
jeka94
Velocity

Hope this helps
7 0
4 years ago
Read 2 more answers
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