Hey there!
To solve this question, lets convert 108 km/h into meters per second.
1 km/h is equal to 0.277778 m/s
To convert 108 km/h into m/s, we just multiply 0.277778 by 108.
0.277778 × 108 = 30.000024
So, the train is travelling at approximately 30 meters per second.
Thank you!
Answer:
5 x 10⁻⁷N
Explanation:
Given parameters:
Mass of object 1 = 100kg
Mass of object 2 = 300kg
Distance = 2m
Unknown:
Force of gravitational attraction between the objects = ?
Solution:
From Newton's law of universal gravitation we derive an expression:
Fg =
G is the universal gravitation constant = 6.67 x 10⁻¹¹
m is the mass
r is the distance between the bodies
Now insert the parameters and solve;
Fg = 6.67 x 10⁻¹¹ x
= 5 x 10⁻⁷N
Answer:
Correct answer: A.) V = - 16.6 m/s down
Explanation:
Given:
V₀ = 3 m/s initial velocity
t = 2 seconds
g = 9.8 m/s²
V(t) = V(2) = ?
The movement described is a vertical upward shot
For velocity at any time is valid the next formula
V = V₀ - g · t
V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down
Under condition that it has a enough drop height with respect to the ejection point.
God is with you!!!
Given: Mass m = 5.00 Kg; Height h = 12 m; Time t = 15 s
Required: Power P = ?
Formula: P = Fd/t = mgh/t
P = (5.0 Kg)(9.8 m/s²)(12 m)/15 s
P = 39.2 Kg.m²/s² or
P = 39.2 J