Question

A car's velocity changes from 0 m/s to 40 m/s in 5 seconds. What is the average acceleration of the car? (Show work)

Answer 1

(vf-vi) ÷ t = a

(40-0) ÷ 5 = 8m/s²

Answer 2

Answer:

Acceleration, $a=8\ m/s^2$

Explanation:

Given that,

Initial velocity of the car, u = 0

Final velocity of the car, v = 40 m/s

Time taken, t = 5 s

Let a is the acceleration of the car. It can be calculated using first equation of motion as :

v = u + at

v = at

40 = a × 5

$a=8\ m/s^2$

So, the acceleration of the car is $8\ m/s^2$. Hence, this is the required solution.