Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrostatic force of m
1 answer:
You might be interested in
The amount of Li present to start the reaction is 55.18g
<u>Explanation:</u>
2Li + Br₂ → 2LiBr
Molecular weight of Br₂ = 159.808 g/mol
Mass of Br₂ present = 225 g
Moles of Br₂ present during the reaction = 225 / 159.808
m = 1.4
Molecular weight of LiBr = 86.845 g/mol
Mass of LiBr formed = 690 g
moles of LiBr produced = 690 / 86.845
m(LiBr) = 7.95
According to the balanced equation, 2 molecules of Li reacts to for 2 molecule of LiBr
So, 7.95 moles of LiBr would require 7.95 moles of Li
The molecular weight of Li is 6.941 g/mol
Thus, the amount of lithium present to start the reaction is
Therefore, the amount of Li present to start the reaction is 55.18g
(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.
(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.
<h3>Work done in moving the charge from C to A</h3>
W = Fd
W = Kq²/d
- from 0 origin to C, d = √(5² + 5²) = 7.07 m
- from 0 origin to A, d = 5 m
W(C to A) = W(0 to C) + W(0 to A)
- from 0 origin to D, d = √(5² + 5²) = 7.07 m
- from 0 origin to B, d = 5 m
W(D to B) = W(0 to D) + W(0 to B)
W(D to B) = 7.62 x 10⁻³ J
Learn more about work done here: brainly.com/question/25573309
#SPJ1