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Gwar [14]
2 years ago
13

Can someone help please?

Mathematics
1 answer:
Marina CMI [18]2 years ago
6 0

Answer:

  g(7) = 16

Step-by-step explanation:

When evaluating piecewise-defined functions, the first step is to determine which domain the value of the independent variable falls into. Then the associated function is evaluated in the usual way.

__

For x=7, the applicable domain is (2, ∞). This means the applicable function is ...

  g(x) = (x +1)(x -5)

For x=7, this is ...

  g(7) = (7 +1)(7 -5) = (8)(2)

  g(7) = 16

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A student number system for a county requires that the student number be 5 characters.
Radda [10]

Answer:

131040

Step-by-step explanation:

10*9*8*7*26

=131040

5 0
2 years ago
A ball bearing has mass 0.44 pounds. 1 kg = 2.2 pounds. <br>​
torisob [31]

Answer:

  (i) 0.2 kg

  (ii) kg/cm³

  (b) 2.29 kg

Step-by-step explanation:

This problem gives you relations between units, and the formulas for density and mass. It is asking you to make use of these relations in various mass and density calculations.

<h3>(a)(i)</h3>

The relationship between kg and pounds can be used to write a units conversion multiplier. It will have numerator equal to denominator, but will have units such that multiplying by it will give the units you want.

  0.44 pounds × multiplier = __ kg

  0.44 pounds × (1 kg)/(2.2 pounds) = (0.44/2.2)(1 kg)

  0.44 pounds = 0.2 kg

__

<h3>(a)(ii)</h3>

The formula can be used to find the units of interest:

  Density = mass/volume

  units of density = (units of mass)/(units of volume)

  units of density = kg/cm³

__

<h3>(b)</h3>

Using the given formula with the given value of L, we find the volume to be ...

  V = 4(1.40 cm)(3 -1.40 cm)² = 14.336 cm³

Then the mass is ...

  mass = volume × density

  mass = (14.336 cm³)×(0.160 kg)/(1 cm³) = 2.29376 kg

The mass is about 2.29 kg.

_____

<em>Additional comment</em>

Often you will see density in terms of kg/m³ or g/cm³. Water has a density of about 1 g/cm³ or 1000 kg/m³. The most dense non-radioactive element in the periodic table is osmium, with a density of about 22.6 g/cm³, or 0.0226 kg/cm³. The material in part (b) of this problem has a density about 7 times that, so is clearly not from Earth.

7 0
2 years ago
Write the three numbers less then 40 that have 2 and 5 as factors
ozzi
No. which have factors 2 & 5 have 2 & 5 as their prime factor
therefore, No. are :
2*5 = 10
2*5*2 = 20
2*5*3 = 30
3 0
3 years ago
A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0
3 years ago
gas prices decreased this week from $4 per gallon to 3.80 dollars per gallon what is the percent decrease​
evablogger [386]

Answer: 5%

Is the percentage

5 0
2 years ago
Read 2 more answers
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