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Gwar [14]
2 years ago
13

Can someone help please?

Mathematics
1 answer:
Marina CMI [18]2 years ago
6 0

Answer:

  g(7) = 16

Step-by-step explanation:

When evaluating piecewise-defined functions, the first step is to determine which domain the value of the independent variable falls into. Then the associated function is evaluated in the usual way.

__

For x=7, the applicable domain is (2, ∞). This means the applicable function is ...

  g(x) = (x +1)(x -5)

For x=7, this is ...

  g(7) = (7 +1)(7 -5) = (8)(2)

  g(7) = 16

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Which of the following statements are true?
lara31 [8.8K]

I believe it is C, as the graphs do look the same.

7 0
3 years ago
Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always
DIA [1.3K]

Answer:

always true.

the expression will always be equal to +5 because -p+p is zero

at any given value to p, the value is constantly +5

8 0
2 years ago
Read 2 more answers
Cos(0°) = sin(0°) = tan(0°) =
MrMuchimi
Cos(0)= 1
sin(0)= 0
tan(0)= 0

P.S I don’t have the degree symbol on my phone, sorry.
4 0
3 years ago
Find the set below using A=(5,6,9), and so on (Explanation is in picture)
anzhelika [568]

The result is: {5,6,9}

Step-by-step explanation:

Given

U = {0,1,2,......,10}

A = {5,6,9}

B = {0, 6, 7, 10}

We have to find

(A∩B)U(A∩B')

First of all,

<u>B':</u>

B' = U -B = {0,1,2,......,10} -  {0, 6, 7, 10}

= {1,2,3,4,5,8,9}

<u>A∩B':</u>

A∩B' = {5,6,9} ∩ {1,2,3,4,5,8,9}

= {5,9}

<u>A∩B:</u>

A∩B = {5,6,9} ∩ {0, 6, 7, 10}

={6}

At the end we have to find union

(A∩B)U(A∩B') = {6} U {5,9}

(A∩B)U(A∩B') = {5,6,9}

Hence,

The result is: {5,6,9}

Keywords: Sets , Union

Learn more about sets at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

8 0
3 years ago
Số tiếp theo (next number?): 25 50 99 196 388
Delvig [45]

Answer:

The correct answer is - 768.

Step-by-step explanation:

The given question is based on a specific pattern present in between the numbers in the given series -

Series = 25 50 99 196 388

to find - next number in series

let us find the relation between the initial two number:

25 - 50, here number 50 is two times of 25 or (x*2-0)

relation between 2nd and 3rd number:

50 - 99, here 99 is two times of 50 minus 1 or (x*2-1)

relation between 3rd and 4th number:

99 - 196, here 196 is two times of 99 minus 2 or (x*2-2)

relation between 4th and 5th number:

196 - 388, here 388 is the two times of 196 minus 4 or (x*2-4)

So on this pattern, the next number would be = x*2-8

388*2-8

= 768

5 0
2 years ago
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