4.7944 x 10^2 hope this helps!
Answer:
no because on is equal to 3 when plugged in and the other is equal to 4 when plugged in.
Step-by-step explanation:

Answer:
The value of <em>c</em> is
.
Step-by-step explanation:
The perfect square of the difference between two numbers is:

The expression provided is:

The expression is a perfect square of the difference between two numbers.
One of the number is <em>x</em> and the other is √<em>c</em>.
Use the above relation to compute the value of <em>c</em> as follows:
![x^{2}-15x+c=(x-\sqrt{c})^{2}\\\\x^{2}-15x+c=x^{2}-2\cdot x\cdot\sqrt{c}+c\\\\15x=2\cdot x\cdot\sqrt{c}\\\\15=2\cdot\sqrt{c}\\\\\sqrt{c}=\frac{15}{2}\\\\c=[\frac{15}{2}]^{2}\\\\c=\frac{225}{4}](https://tex.z-dn.net/?f=x%5E%7B2%7D-15x%2Bc%3D%28x-%5Csqrt%7Bc%7D%29%5E%7B2%7D%5C%5C%5C%5Cx%5E%7B2%7D-15x%2Bc%3Dx%5E%7B2%7D-2%5Ccdot%20x%5Ccdot%5Csqrt%7Bc%7D%2Bc%5C%5C%5C%5C15x%3D2%5Ccdot%20x%5Ccdot%5Csqrt%7Bc%7D%5C%5C%5C%5C15%3D2%5Ccdot%5Csqrt%7Bc%7D%5C%5C%5C%5C%5Csqrt%7Bc%7D%3D%5Cfrac%7B15%7D%7B2%7D%5C%5C%5C%5Cc%3D%5B%5Cfrac%7B15%7D%7B2%7D%5D%5E%7B2%7D%5C%5C%5C%5Cc%3D%5Cfrac%7B225%7D%7B4%7D)
Thus, the value of <em>c</em> is
.
Answer:
x = 16, y = 22: So C.
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
When graphing it you can see that (3, 4) is clearly a solution. The proper equation using slope intercept form is y= 2/3x + 2.