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2 years ago

The data below represent the number of days absent per year in a population of three employees of a small company:

Mathematics

1 answer:

love history [14]2 years ago

8 0

The sampling distribution is illustrated below.

<h3>How to illustrate the sampling?</h3>

Based on the information given, the population is illustrated as 1, 4, 7. The sample without replacement will be:

<u>Sample Mean</u>

1 and 4. 2.5

1 and 7. 4

4 and 7. 5.5

The population mean will be:

= (1 + 4 + 7)/3

= 4

The sample mean is an unbiased estimator of the population mean.

The sampling with replacement illustrates that the mean will be:

= 36/9 = 4

Also, when n = 3, the number of samples will be:

= 3³ = 27

Learn more about sampling on:

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nlexa [21]

Answer:

From my understanding i think it is 315, but I think I'm wrong.

Step-by-step explanation:

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3 years ago

Read 2 more answers

125 cm to 87.4 cm percent of change

netineya [11]

Answer:

% Change = (87.5 - 125) / 125 * 100%

= -37.5 / 125 * 100%

= -0.3 * 100%

= -30 %

The percent change is -30 % or 30% decrease.

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3 years ago

What is $9 discounted to $4

Dafna11 [192]

Answer:

123

Step-by-step explanation:

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4 years ago

The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?

svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that $r = 0.16$

$V(t) = V(0)(1-r)^{t}$

$V(t) = V(0)(1-0.16)^{t}$

$V(t) = V(0)(0.84)^{t}$

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

$V(t) = V(0)(0.84)^{t}$

$0.5V(0) = V(0)(0.84)^{t}$

$(0.84)^{t} = 0.5$

$\log{(0.84)^{t}} = \log{0.5}$

$t\log{0.84} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.84}}$

$t = 3.98$

The half life of the car is 3.98 years.

7 0

3 years ago

Metal A has a density of 12.7 g/cm3.

stira [4]

Using the given information, the density of metal B is 8.58 g/cm³

<h3>Calculating density </h3>

From the question, we are to determine the density of metal B

From the given information,

55 g of metal A is combined with metal B to create an alloy with mass 90 g

∴ Mass of metal B in the alloy = 90 g - 55 g = 35 g

Now, we will determine the volume of metal A in the alloy

Using the formula,

Density = Mass / Volume

∴ Volume = Mass / Density

Volume of metal A in the alloy = 55/12.7

Volume of metal A in the alloy = 4.33 cm³

Then, we will determine the volume of the alloy

Volume of the alloy = 90/10.7

Volume of the alloy = 8.41 cm³

∴ Volume of metal B in the alloy = 8.41 cm³- 4.33 cm³

Volume of metal B in the alloy = 4.08 cm³

Now, for the density of metal B

Density = mass / volume

Density of metal B = 35 / 4.08

Density of metal B = 8.58 g/cm³

Hence, the density of metal B is 8.58 g/cm³.

Learn more on Calculating density here: brainly.com/question/13986137

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5 0

2 years ago