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Nezavi [6.7K]
3 years ago
15

How many seconds are in a 5.5 ms

Chemistry
1 answer:
deff fn [24]3 years ago
8 0

Answer:

0.0055 seconds

Explanation:

To answer this question you need to know the equivalence:

1 second (s) = 5.5 (miliseconds) (ms)

Then you use the conversion factor:

-Put the value given and the units:

5.5ms

- Put in the denominator the equivalence with the same units:

5.5ms*\frac{}{1000ms}

- Put in the numerator the unit at which you want to convert the value given:

5.5ms*\frac{1s}{1000ms}

- Then multiply and divide the quantities:

5.5ms*\frac{1s}{1000ms}=0.0055 s

Note that the same units in numerator and denominator are cancelled.

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A 75 um thick polysulphone microporous membrane has an average porosity of E 0.35. Pure water flux through the membrane is 35 m'
Paul [167]

Explanation:

The given data is as follows.

           Water flux, J_{w} = 25 m^{3}/m^{2}h

                                       = \frac{25}{3600} m^{3}/m^{2}h

So, let velocity (u) = \frac{25}{3600} m/s = 6.9 \times 10^{-3}

             \rho = 998 kg/m^{3}

             Pore size, d = 0.8 \times 10^{-6} m

             \mu = 0.9 cP = 9 \times 10^{-4} Pa.s

Hence, calculate the reynold number as follows.

                 R_{e} = \frac{\rho \times u \times d}{\mu}            

                        = \frac{998 kg/m^{3} \times 6.9 \times 10^{-3} \times 0.8 \times 10^{-6} m}{9 \times 10^{-4} Pa.s}    

                        = 612.1 \times 10^{-5}

                        = 0.006

This means that the flow is laminar.

Now, we use Hagen-Poiseuille equation as follows.

             J_{w} = \frac{\varepsilon \times d^{2}}{32 \times \mu \times \tau} \times \frac{\Delta P}{L_{m}}

where,     \varepsilon = membrane porosity = 0.35

                              d = 0.8 \times 10^{-6} m

                       \Delta P = 2 \times 10^{5} Pa

                      \mu = 9 \times 10^{-4}

                      \tau = tortuosity

                      L_{m} = membrane thickness = 75 \times 10^{-6} m

                    \frac{25}{3600} = \frac{0.35 \times (0.8 \times 10^{-6})}{32 \times (9 \times 10^{-4}) \times \tau}

                            \tau = 3.73

Hence, the tortuosity factor of the pores is 3.73.

As flow resistance = R_{m}

               J_{w} = \frac{\Delta P}{r \times R_{m}}

               R_{m} = 3.2 \times 10^{10} m^{-1}

Water permeability is represented by L_{p}.

                    J_{w} = L_{p} \times \Delta P  

             6.9 \times 10^{-3} = L_{p} \times 2 \times 10^{5} Pa  

              L_{p} = 3.45 \times 10^{-8} m^{3}/m^{2}s Pa

Therefore, the resistance to flow is 3.2 \times 10^{10} m^{-1} and its water permeability is 3.45 \times 10^{-8} m^{3}/m^{2}s Pa.

3 0
3 years ago
If a sample has a mass of 1.25 x 102 g and a volume of 51 mL, what is its density?
Dafna11 [192]

Answer:

<h2>2.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

d =  \frac{m}{v}  \\

We have

d =  \frac{1.25 \times  {10}^{2} }{51}  \\  = 2.45098..

We have the final answer as

<h3>2.45 g/mL</h3>

Hope this helps you

3 0
3 years ago
Which of these is a typical property of a substance that is composed of atoms that are held together by covalent bonds?
iragen [17]

Answer:

The last choice.

Explanation:

It does not conduct electricity in any form.

They have no free electrons and do not ionise.

4 0
4 years ago
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Which class of biomolecule do the molecules in the table belong to?
kondaur [170]
The oythagorean theroem
8 0
3 years ago
Fungi do not contain chlorophyll. True False
ivolga24 [154]
The answer to your question is false

4 0
4 years ago
Read 2 more answers
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