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Serga [27]
3 years ago
9

Which of the following is a possible formula unit? (2 points) Select one: a. PbO b. Li2B c. Al2Pb3 d. ClO

Chemistry
1 answer:
storchak [24]3 years ago
7 0

Answer:

a. PbO.

Explanation:

  • The formula unit of a stable chemical compound should maintain that the overall charge of the compound is zero <em>(not charged)</em>.
  • The formula unit of a compound is represented by the lowest ratio numbers of the ions forming the compound.

<em>Choice a:</em> is the right answer PbO

  • That lead is divalent cation Pb²⁺ and O is considered as a divalent anion O²⁻.
  • So, the formula unit contains Pb:O with a ratio of 1:1 (PbO)

<em>Choice b: </em>is a wrong choice Li₂B

  • The lithium cation is a monovalent cation Li¹⁺ and boron is a trivalent cation B³⁺, so we can not do that.

<em>Choice c:</em> is a wrong choice Al₂Pb₃

  • that Al is a trivalent cation Al³⁺ and Pb is a divalent cation Pb²⁺, so we can not do this for the two cations.

<em>Choice d:</em> is a wrong choice ClO

  • that Cl may act as Cl¹⁺ and O acts as O²⁻, so the right formula unit should be Cl₂O.
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Object A has a temperature of 287 Kelvin, object B has a temperature of 374 Kelvin. In what direction will thermal energy flow?
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Una disolución contiene 50 gramos de KOH en 0.25 L de Determine la Molaridad de la disolución
snow_tiger [21]

Answer:

1. 3.56 M.

2. 0.99 M.

Explanation:

¡Hola!

1. En este caso, dado que la molaridad de una solution es calculada por medio de la siguiente ecuación:

M=\frac{n}{V}

Es posible calcular la molaridad de 50 gramos de hidróxido de potasio primero calculando las moles en dicha masa por medio de la masa molar:

n=50.0gKOH*\frac{1molKOH}{56.11gKOH}=0.891molKOH

Luego, dado el volumen de la solución, podemos calcular la molaridad:

M=\frac{0.891mol}{0.25L}=3.56M

2. En este segundo ejercicio, procedemos de la misma manera, pues primero calculamos las moles de nitrato de potasio:

n=75gKNO_3\frac{1molKNO_3}{101.1gKNO_3}=0.742mol

Luego, calculamos la molaridad justo como se hizo anteriormente:

M=\frac{0.742mol}{0.35L} \\\\M=0.99M

Best regards!

3 0
3 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
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