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GalinKa [24]
2 years ago
10

Match the expression to its simplified form.

Mathematics
1 answer:
kirill115 [55]2 years ago
8 0
5^-2=1/5^2=1/25
2^-4=1/2^4=1/16
5^3=5*5*5=125
2^5=2*2*2*2*2=32

Hope this helped :)
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Answer:The answeris 66 inches.


Step-by-step explanation:


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Okay so you can add up all the marbles to find a rate and divide.
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Lisa is making her famous chocolate chip brownies. The recipe calls for 2 cups of chocolate chips, but Lisa can only find her La
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Step-by-step explanation:

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3 years ago
Suppose the size of a population of mustard plants is 6,000. According to genetic drift theory, what is the probability that a n
andre [41]

Answer:

1/12,000

Step-by-step explanation:

Data provided in the question:

Size of a population of mustard plants = 6,000

Now,

According to genetic drift theory

The probability that a newly-arisen mutation will become fixed is given using the formula

⇒ 1 ÷ [ 2 × Size of a population of mustard plants ]

⇒ 1 ÷ [ 2 ×6,000 ]

⇒ [ 1 ÷ 12,000 ]

Hence,

probability that a newly-arisen mutation will become fixed in this population is 1/12,000

3 0
3 years ago
Tain has a great literary tradition that spans centuries. One might assume, then, that Britons read more than citizens of other
tresset_1 [31]

Answer:

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

z=3.02  

p_v =P(Z>3.02)=0.00127  

The p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of Canadians is not significantly higher than the porportions of readers at Britons.  

Step-by-step explanation:

1) Data given and notation  

X_{1}=0.86*1004 represent the number of Canadians randomly sampled by Gallup that read at least one book in the past year

X_{2}=0.81*1009 represent the number of Britons randomly sampled that read at least one book in the past year

n_{1}=1004 sample of Gallup selected

n_{2}=1009 sample of Britons selected

p_{1}=0.86 represent the proportion of Canadians randomly sampled by Gallup that read at least one book in the past year

p_{2}=0.81 represent the proportion of Britons randomly sampled that read at least one book in the past year

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion for men with red/green color blindness is a higher than the rate for women  , the system of hypothesis would be:  

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{0.81+0.86}{2}=0.835

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.86-0.81}{\sqrt{0.835(1-0.835)(\frac{1}{1004}+\frac{1}{1009})}}=3.02  

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =P(Z>3.02)=0.00127  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of Canadians is not significantly higher than the porportions of readers at Britons.  

5 0
3 years ago
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