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Fantom [35]
1 year ago
5

In a group of 60 students, 18 students take Algebra I, 20 students take

Mathematics
1 answer:
melamori03 [73]1 year ago
7 0

Answer:

32...................

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What is the decimal of 32/100​
katen-ka-za [31]

Answer:

0.32

Step-by-step explanation:

Simply divide 32 into 100 and get 0.32

you could put it into a calculator or write it out and divide.

7 0
3 years ago
Someone please help. It is easy
Juli2301 [7.4K]
Alright. So we have 2 eggs at 2.49 each. That is $4.98. We have .25 pounds cheese priced at $13.40 per pound. 13.40 x .25 = $3.35. Then we have juice at $5.49. If we add those up we get: 4.98+3.35+5.49=$13.82. Then we get $0.75 in change, so if we add $13.82 and 0.75 we get: $14.57

The answer is $14.57.
Brainliest???
5 0
3 years ago
How to solve <br> 6x - 17
AveGali [126]

Answer:

you can

Step-by-step explanation:

they are not like terms because the number 6 has and x next to it and 17 doesn't

6 0
2 years ago
Read 2 more answers
Answer to this question please?
egoroff_w [7]
7 mphs faster...............
7 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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