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Pavel [41]
3 years ago
10

Perimeter: 30 in X 13 in 5 in

Mathematics
1 answer:
Julli [10]3 years ago
4 0
Perimeter is adding up all the dues together
if it’s 30
13+5=18
30-18=12
x is 12
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What is the slope of the line that passes through (-3,-7) and (1,9)
Rus_ich [418]

To find slope, use the formula:

(y2-y1)/x2-x1)

So here is what it will look like:

(9--7)/(1--3)

Since you are subtracting a negative, then it turns unto a positive so you are adding the numbers together.  

(9+7)/1+3)

16/4

4

The slope of the line is 4/1 or 4.  Which means that you will go up or "rise" 4 and go to the left or "run" 1.


Hope this helps!

4 0
3 years ago
When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

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5 0
3 years ago
X-2y=10 x+3y=5 please hellppppppp
Marta_Voda [28]

Answer:

x=8,y=-1

Step-by-step explanation:

x-2y=10

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10+2y+3y=5

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3 0
3 years ago
Read 2 more answers
twice the smaller of two consecutive integers increased by the larger integer is at least 25. what is the number?
stira [4]
x,x+1-\ two \ consecutive\ numbers\\\\
2x+x+1\geq25\\\\
3x+1\geq25\ \ \ | subtract\ 1\\\\
3x\geq24\ \ \ | divide\ by\ 3\\\\
x\geq8\\\\
It\ is\ 8\ or\ greater\ number.
3 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
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