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babunello [35]
1 year ago
15

Triangle U S T is shown. Angle U S T is 100 degrees. The length of U S is 9, the length of S T is 10, and the length of U T is s

.
Which equation correctly uses the law of cosines to solve for the length s?

92 = s2 + 102 – 2(s)(10)cos(100°)
9 = s + 10 – 2(s)(10)cos(100°)
102 = s2 + 100 – 2(s)(10)cos(100°)
s2 = 92 + 102 – 2(9)(10)cos(100°)
Mathematics
1 answer:
Vladimir [108]1 year ago
6 0

By solving through law of cosines the length s can be written as s^{2} =9^{2} +10^{2} -2*9*10cos(100).

Given the length of US is 9, the length of ST is 10 and the length of UT is s and the angle UST is 100 degrees.

According to law of cosines a length can be written as c^{2} =a^{2} +b^{2} -2abcos g

where c is the side opposite to the given angle and a and b are other sides , g is the angle given.

s^{2} =9^{2} +10^{2} -2*9*10cos(100)

where s is the length of the side opposite to the angle given, the length of other sides are 9 and 10 where the angle is 100.

Hence the fourth option is correct which is s^{2} =9^{2} +10^{2} -2*9*10cos(100).

Learn more about trigonometric functions here brainly.com/question/24349828

#SPJ10

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Todd wants to make a snack of a number of grapes and slices of cheese. He knows that each grape has 2 calories. The slice of che
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Answer:

The answer to your question is:

a) C = 2g + 155c

b) g = 25 grapes

c) c = 3

Step-by-step explanation:

Data

grapes = g = 2 calories

cheese = c = 155 calories

a) Equation, we consider the amount of grapes and the calores given.

Total calories = C = 2g + 155c

b) We consider that the slices of cheese stays the same

                       2g + 155 = 205

                       2g = 205 -155

                        2g = 50

                        g = 50/2 = 25 grapes

c) Then the number of grapes stays the same

                       2(25) + 155c = 515

                       50 + 155c = 515

                       155c = 515 - 50

                        155c = 465

                        c = 465/155

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