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2 years ago

5

Suppose a population is known to be normally distributed with a mean, μ, equal to 116 and a standard deviation, σ, equal to 14.

Approximately what percent of the population would be between 130 and 144?

1 answer:

Yuki888 [10]2 years ago

4 0

Excuse me sir I believe the answer is 20 plus the
Patty cakes on your bubble bums like a sir baby with a mustache

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Express .05 as a fraction in similest form

Alja [10]

0.05 = 5% = 5/100

Simplify 5/100 and you get 1/20.

Hope this helps & good luck. :)

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4 years ago

Read 2 more answers

Which of the following sets of integers is listed in descending order?

valentina_108 [34]

Your answer is J. because descending means it’s getting smaller

6 0

3 years ago

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2. Tina uSUally brings her children every Sunday afternoon at the children's park in their barangay. The park is 350m Iong and 2

Verdich [7]

Answer: kindly check explanation

Step-by-step explanation:

Given the following :

Total area of parknand path way = 74,464 m2.

Dimension of park = 350m by 200m

Using the area of rectangle formula:

Area = Length * width

Area of park = 350m * 200m

Area of park = 70,000

Area of path = (74,464 - 70,000) = 4,464m2

Since path has uniform width, then width of the the path is sqrt(4464) = 66.8m

2.) the path of the park seems a bit narrow, hence, I wouldn't love children to bike and jog in such a narrow path

4 0

4 years ago

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

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3 years ago

WHAT IS 817373763647837466367828390487273839288738939393872803928 Factorial

ad-work [718]

Answer: No one will ever know that

Step-by-step explanation:

Seriously even Google doesn’t know it

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3 years ago