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Leya [2.2K]
2 years ago
5

What are the environmental impacts of chemical industries using distillation to separate chemical solutions?

Chemistry
1 answer:
Gwar [14]2 years ago
7 0

Answer:

The production process often produces offensive odours and may also create by-products that can contaminate air and ground water. Many industrial separation processes have requirements and consequences that influence where they are located.

Explanation:

hope it's helpful to you

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The thermometer in the picture reads, "19.9 degrees Celsius".
GalinKa [24]

Answer:

Sorry but i can't help

Explanation:

i need to really finesh s

6 0
3 years ago
Which of these substances are molecules?
Tamiku [17]

Answer:

c) none of them

Explanation:

because H20, N2 , O2 are all molecules except NaCl so there is no answers like ( 1, 3, and4 ) so we choose none of them.

6 0
3 years ago
The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L.
valentinak56 [21]

Answer:a) 0.1 mole. b) 4g. c) 2% d)  196 mL

Explanation: in 200mL , 0.1mole

mw NaOH = 40g/mol —> 4g in 0.1 mole

4g in 200mL so 2g in 100mL

density NaOH = 1g/mL so if 4g in 200 mL,  4mL , 196 mL water

5 0
2 years ago
What is the relationship between electron configuration and valence electrons?
Leya [2.2K]

Answer:

The electrons that occupy the outermost shell of an atom are called valence electrons. Valence electrons are important because they determine how an atom will react. By writing an electron configuration, you'll be able to see how many electrons occupy the highest energy level .

3 0
2 years ago
4. Given the balanced equation: 2Na + S → Na₂S
PtichkaEL [24]

Answer:

Option D. 30 g

Explanation:

The balanced equation for the reaction is given below:

2Na + S —> Na₂S

Next, we shall determine the masses of Na and S that reacted from the balanced equation. This is can be obtained as:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of S = 32 g/mol

Mass of S from the balanced equation = 1 × 32 = 32 g

SUMMARY:

From the balanced equation above,

46 g of Na reacted with 32 g of S.

Finally, we shall determine the mass sulphur, S needed to react with 43 g of sodium, Na. This can be obtained as follow:

From the balanced equation above,

46 g of Na reacted with 32 g of S.

Therefore, 43 g of Na will react with = (43 × 32)/46 = 30 g of S.

Thus, 30 g of S is needed for the reaction.

8 0
2 years ago
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