Reaction between Iron and oxygen to form iron (iii) oxide is written as;
4Fe (s) + 3O2(g) = 2Fe2O3(s)
1mole of iron contains 56 g, hence,
28.1 g of iron contains 28.1/56 = 0.502 moles
To get the moles of iron (iii) oxide formed we use the mole ratio
mole ratio of iron : iron (iii) oxide = 4 : 2
Therefore, moles of iron(iii) oxide will be given by 0.502×2/4 = 0.251 moles
hence, the answer is 0.251 moles of iron(iii) oxide
Answer:
<em>The answer to your question is </em><em>c. H2O</em>
Explanation:
<em>a. CaCO3 ----> Calcium Carbonate is obviously not a binary compound because it contains more than two elements. </em>
<em>b. CuSO4 ----> CuSO4 stands for copper(II) sulfate. Sulfate is the polyatomic ion SO4 -2.</em>
<em>c. H2O ----> Binary molecular compounds are composed of only two elements. Examples are H2O, NO, SF6 etc. </em>
<em>d. Pb(NO3)2 ----> Lead(II) nitrate is an inorganic compound with the chemical formula Pb(NO3)2.</em>
<em>I hope this helps and have a great day!</em>
<em>i think the answer is b </em>
Na has a +1 charge, and O has a -1 charge.
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Hope this helped! Good luck! :)