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ikadub [295]
3 years ago
10

What is △n for the following equation in relating Kc to Kp?

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
7 0

Answer:

-1  

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2Na_{(s)}+2H_2O_{(l)}\rightleftharpoons 2NaOH_{(aq)}+2H_2_{(g)}

<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)  = (2+1)-(2+2) = -1  </u>

<u></u>

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Correct question:

At constant pressure, which of these systems do work on the surroundings?

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Work done by a system on the surroundings at a constant pressure is given as;

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Part (b)

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Part (c)

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Part (d)

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