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ikadub [295]
3 years ago
10

What is △n for the following equation in relating Kc to Kp?

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
7 0

Answer:

-1  

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2Na_{(s)}+2H_2O_{(l)}\rightleftharpoons 2NaOH_{(aq)}+2H_2_{(g)}

<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)  = (2+1)-(2+2) = -1  </u>

<u></u>

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when applied to a dish, soap makes grease soluble in water. which explanation correctly supports the role of intermolecular forc
ankoles [38]
This is possible because of the emulsifying properties present in soap. This property is caused by the hydrophilic end and hydrophobic end of a soap molecule. Grease is able to be dissolved in the water because it is attracted to the hydrophobic end of the soap molecule.
7 0
3 years ago
If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?
sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2HgO\rightarrow 2Hg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2HgO = Total mass of 2Hg+O_2

As we are given :

The mass of HgO = 25.3 grams

The mass of Hg = 23.4 grams

So,

2\times 25.3g=2\times 23.4g+\text{Mass of }O_2

50.6g=46.8g+\text{Mass of }O_2

\text{Mass of }O_2=3.8g

Therefore, the mass of oxygen formed must be 3.8 grams.

6 0
3 years ago
What is the percent mass oxygen in calcium carbonate (CaCo3)?
Gnoma [55]
  <span>Step 1 is to determine the mass of each part 
Mass of Ca is 40.08 g 
Mass of C is 12.01 g 
Mass of O is 16.00 x 3 = 48.00 g 
Step 2 is to determine the total mass of the compound 
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g 

Step 3 is to determine the % of each part using the following formula: 
Mass of part / total mass x 100 = 

40.08 / 100.09 x 100 = 40.04 % Ca 

12.01 / 100.09 x 100 = 12.00 % C 

48.00 / 100.09 x 100 = 47.96 % O 

Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :) 
40.04 
+12.00 
+47.96 
=100.00</span><span>
</span>
4 0
3 years ago
Read 2 more answers
I NEED HELP RIGHT NOW
PolarNik [594]
There are a total of 4 elements
7 0
3 years ago
a piece of food is burned in a calorimeter that contains 200.0g of water. If the temperature of the water rose from 65.0°C to 83
Flauer [41]

Answer: 15062.4 Joules

Explanation:

The quantity of heat energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of food = 200.0g

C = 4.184 j/g°C

Φ = (Final temperature - Initial temperature)

= 83.0°C - 65.0°C = 18°C

Then, Q = MCΦ

Q = 200.0g x 4.184 j/g°C x 18°C

Q = 15062.4 J

Thus, 15062.4 joules of heat energy was contained in the food.

4 0
3 years ago
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