How many moles are in 17.31 g of NaHCO,?
1 answer:
Answer:
0.33moles
Explanation:
RAM of;
Na = 23, H=1, C=12, O=16
molar mass of NaHCO= 23+1+12+16= 52g/mol
mole= mass / molar mass
mole = 17.31/52
mole= 0.33moles
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