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dlinn [17]
3 years ago
12

How many moles are in 17.31 g of NaHCO,?

Chemistry
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

0.33moles

Explanation:

RAM of;

Na = 23, H=1, C=12, O=16

molar mass of NaHCO= 23+1+12+16= 52g/mol

mole= mass / molar mass

mole = 17.31/52

mole= 0.33moles

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lys-0071 [83]

Answer : Option 4) CO_{2}_{(aq)}

Explanation : CO_{2}_{(aq)} is the only sample of matter which can be classified as a solution. As the solution can be defined as a liquid mixture which contains a minor component (the solute) that is uniformly distributed within the major component (the solvent).

In this case, the solute is CO_{2} which is dissolved in water which acts as an solvent. Also, it has a subscript which is aq. which means aqueous, is often given to the solution in which the solvent is water.

Therefore, CO_{2}_{(aq)} is the correct answer.

4 0
4 years ago
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How much heat is needed to raise the temperature of 100g of an iron from 25°C to
Black_prince [1.1K]

Answer:

382.5J

Explanation:

<em>Use the formula:</em>

E = mcΔθ or Q = mcΔT

m = 100g

c = 0.45 J/g°C

ΔT or Δθ = 110 - 25 = 85°

<em>Sub in the values:</em>

E = 100 × 0.45 × 85

= 382.5J

5 0
3 years ago
PLEASE HELP!! ASAP!! WILL MARK BRAINLIEST!!!
sdas [7]

Answer:

Alkali metals are soft and have low melting points.

7 0
3 years ago
If two atoms have an electronegativity difference of 1.3, what type of bond would form between them?
Debora [2.8K]

Answer:

The correct answer is b polar covalent

Explanation:

When two atoms joined by covalent bond has difference in their electronegativities at that time polarity arise.

    When the electronegativity difference is low such as 1.3 then the polar bond formed by the two atoms are called polar covalent bond.For example H2O

 on the other hand polar bond formed by two atoms having high difference in their electronegativities is called ionic bond.For example NaCl.

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Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3
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Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

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Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

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