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AVprozaik [17]
3 years ago
14

Question 1. Complete the table.

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0
The picture is the completed table

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Point A on a number line is 12 units to the left of 0. Point B is 9 units to the right of zero. What is the distance between Poi
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I’m pretty sure it’s 21 units
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Given the diagram below solve for x
kifflom [539]

Answer:

8.57

Step-by-step explanation:

y=AC

7/15=11/y

y=23.57

x=y-15

x=8.57

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In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
masha68 [24]

Answer:

1. The amount of ice needed for the sculpture is 18 m³

2. The amount of fabric needed to manufacture the umbrella is 0.757 m²

3. The height of the cone is 37.5 cm

4. The largest possible storage area which is obtained by attaching the storage area to the back of the building is 87.11 m²

Step-by-step explanation:

1. The volume, V, of a rectangular pyramid = \dfrac{1}{3} \cdot B \cdot h

Where:

B = Base area = Length, L  × Width, W

h = Height of the pyramid = 3.6 m

L = 5 m

W = 3 m

The volume = 1/3 × 5 × 3 × 3.6 = 18 m³

The amount of ice needed for the sculpture is 18 m³

2) The surface area of a cone = π·r·s

s = Slant height

r = Radius of the cone's base = 0.4 m

h = The height of the cone = 0.45m

s = √(0.4² + 0.45²) = (√145)/20

The surface area of the cone = π × 0.4 × (√145)/20 = 0.757 m²

The amount of fabric needed to manufacture the umbrella is 0.757 m²

3) The volume, V of the cone = 150 cm³

The base area, A_b, of the cone = 12 cm²

The height of the cone = h

We note that the volume of a cone = \dfrac{1}{3} \cdot A_b \cdot h

Therefore;

\dfrac{1}{3} \times 12 \times  h = 150

4·h = 150

h = 150/4 = 37.5 cm

The height of the cone = 37.5 cm

4) The storage area at the back corner  with four sides = 100 m²

The storage area at the back of the building with three sides = 98 m²

Given that the available riling = 28 m, we have;

For maximum area the four sides should be equal, hence dimension of each side = 28/4 = 7

The area of storage space that can be fenced on four sides at the back corner = 7 × 7 = 49 m²

At the back of the building only three sides need fencing, we therefore have;

The side length = 28/3 = 9\frac{1}{3}

The area fenced = \left 9\frac{1}{3} \right  \times 9\frac{1}{3}  = 87\frac{1}{9} \ m^2 = 87.11 m²

Therefore, the largest possible storage area, 87.11 m², is obtained by attaching the storage area to the back of the building.

5 0
4 years ago
Name four possible solutions to the inequality; X > -1
timama [110]
Really anything below -1
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7 0
3 years ago
What is the y intercept of the line I ready
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Answer:

up and down is y and x is side to side

7 0
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