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avanturin [10]
2 years ago
10

In skunks, stripes (S) is dominant to spots (s) and black coat color (B) is dominant to brown coat color (b). If a skunk that is

homozygous for stripes and heterozygous for black coat color is crossed to a skunk that is homozygous for spots and heterozygous for black coat color, what genotypic and phenotypic ratios would you expect to observe among the offspring
Biology
1 answer:
BaLLatris [955]2 years ago
6 0

The genotypic and phenotypic ratios observed among the skunks offspring are:

Genotypic ratio: 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1

Phenotypic ratio:

Striped Black coat = 9/16

Striped Brown coat = 3/16

Spotted Black coat= 3/16

Spotted Brown coat = 1/16

A cross is made between a striped black coat (SSBB) with spot brown coat (ssbb). Stripes (S) is dominant to spots (s) and black coat color (B) is dominant to brown coat color (b).

In F1 generation its shows a progeny of SsBb.

If shunks of contrasting characteristics like stipe/spot and black coat/brown coat are crossed the F1 progeny would have all Stripped with black coat according to the dominance. This implies that stripes is dominant over spots and black coat is dominant over brown coat . In F2 progeny, there would be some stripes with black coat and spots with brown coat. However, there would be some shunks with recombination of characters such as stripes with brown coats and spotted shunks with a black coats. This depicts that stripe/spot and black/brown coats traits are inherited independently of each other following law of independent assortment. which states that when two traits are taken in a cross the segregation of one trait is independent to the segregation of other characters.

Learn more about dihybrid cross here:

brainly.com/question/8083392

#SPJ4

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