Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
40
Step-by-step explanation:
1. Change 48 cm to mm, which will give you 480 mm
2. Divide 480 mm by 12 mm, that will give you 40
Therefore, Victor needs 40 books to make his desired height.
Answer:
sin(C) = opposite side / hypotenuse
= 15/17
Answer:
1/2
Step-by-step explanation:
So you have 12 bags total.
2 are 1/6 so their total weight is 1/3
2 are 1/3 so their total weight is 2/3
3 are 1/2 so their total weight is 3/2
4 are 2/3 so their total weight is 8/3
1 is 5/6 so their total weight is 5/6
Now add all of these up:
1/3 + 2/3 + 3/2 + 8/3 + 5/6 = 36/6 = 6
Then divide by the number of bags to get the average weight: 6/12 = 1/2
Answer:
20 :3
Step-by-step explanation:
Da distance is 20
80 - 60 = 20 BOOM PEEPS
