Answer:
When x = -2, y = 3
When x = -1, y = 0
When x = 0, y = -3
When x = 1, y = -6
Step-by-step explanation:
Given:
y = -3x - 3
Fill in the table using the following value for x
When x = -2
y = -3x - 3
y = -3(-2) - 3
y = 6 - 3
y = 3
When x = -2, y = 3
When x = -1
y = -3x - 3
y = -3(-1) - 3
y = 3 - 3
y = 0
When x = -1, y = 0
When x = 0
y = -3x - 3
y = -3(0) - 3
y = 0 - 3
y = -3
When x = 0, y = -3
When x = 1
y = -3x - 3
y = -3(1) - 3
y = -3 - 3
y = -6
When x = 1, y = -6
(X-5)2+3(X-5)+9 = 0
let expand the equation
(x)x2-(5)x2 + 3(x)-3(5) + 9 = 0
2x-10+3x-15+9=0
collect like terms
2x+3x-10-15+9 =0
5x-10-6 =0
5x-16=0
5x=0+16
5x=16
divide both side by 5 we have
x=16/5
Using logarithms property of log(x)+log(y)=log(xy)
so here, you can sum the equation to;
so you can simply say that;
and by multiplying (x+6)*(x-6)
and as you know also that;
is same as
so you can simply state it as;
And you can check your work by substituting with 10 instead of x in the original function.
Hope this helps!
Answer:3a. Stu ?
Step-by-step explanation:
Answer:
x = 3
y = 0
Step-by-step explanation:
The method of substitution is when one solves an equation for one of the variables, and then substitutes the expression into the other equation. After doing so, one will solve the other equation for the remaining variable and then backsolve for the first variable.
4x + 2y = 12
x = y + 3
The second equation is already sovled for parameter (x), subttiute this into the other equation,
4(y + 3) + 2y = 12
Distribute,
4y + 12 + 2y = 12
Simplify,
6y + 12 = 12
Inverse operations,
6y + 12 = 12
-12
6y = 0
/6
y = 0
Backsolve for (x), substitute the value of (y) into the equation for (x) and solve,
x = y + 3
x = 0 + 3
x = 3
