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san4es73 [151]
3 years ago
15

What is the pH of a 0.40 M solution of C6H5COOH?

Chemistry
1 answer:
melomori [17]3 years ago
4 0
What are the answer choices?
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In a sulphuric acid (h2so4) - sodium hydroxide (naoh) acid-base titration, 17.3 ml of 0.126 m naoh is needed to neutralize 25 ml
katen-ka-za [31]
The balanced equation for the neutralisation reaction is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
the number of moles of NaOH reacted  - 0.126 mol/L  x 0.0173 L = 0.00218 mol
if 2 mol of NaOH reacts with 1 mol of H₂SO₄ 
then 0.00218 mol of NaOH reacts with - 0.00218 / 2 = 0.00109 mol of H₂SO₄ 
molarity is the number of moles of solute in 1 L solution
therefore if 25 mL contains - 0.00109 mol 
then 1000 mL contains - 0.00109 mol / 25 mL  x 1000 mL = 0.0436 mol/L
therefore molarity of H₂SO₄ is 0.0436 M
4 0
3 years ago
Usually hard but brittle<br> Ionic or covalent
aleksandrvk [35]

Answer:

Ionic

Explanation:  Ionic compounds tend to be hard and brittle while covalent compounds tend to be softer and more flexible.

Hope this helped!

7 0
3 years ago
Read 2 more answers
3) During the day at 27°C a cylinder with a sliding top contains 20.0 liters
tatiyna

Answer:

T_2=12\°C

Explanation:  

Hello there!  

In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:

\frac{T_2}{V_2}=\frac{T_1}{V_1}  

Thus, by solving for the final temperature, T2, and making sure we use the temperatures in Kelvin, we can calculate the final temperature as shown below:

T_2=\frac{T_1V_2}{V_1}  \\\\T_2=\frac{(27+273)K*19L}{20.0L}\\\\T_2=285-273\\\\T_2=12\°C

Best regards!  

Best regards!

4 0
2 years ago
Calculate the vapor pressure of a solution made by dissolving 11.1 g Ca(OH)2 in 1 102 g of water at 25 °C. Vapor pressure of pur
Levart [38]

Answer:

23.15 mmHg.

Explanation:

To solve this question you need to understand that part of Raoult's law in your Chemistry textbook. So, let us delve right into the solution of the question.

We are given parameters such as the mass of Ca(OH)2 to be = 11.1 grams, mass of solvent = 102 grams, the Vapor pressure of pure water= 23.76 mm Hg, temperature = 25°C and vapour pressure of the solution= ??.

The molar mass of Ca(OH)2= 74 g/mol.

The first thing to do is to find the number of moles of Ca(OH)2 and that of water from the formula below;

Mass/ molar mass = Number of moles.

===> Number of moles, n= 11.1/ 74.

Number of moles = 0.15 moles Ca(OH)2.

===> Number of moles, n= 102/ 18.

Number of moles, n= 5.67 moles of water.

Next, we add the two moles together to find the solvent mile fraction since vapour pressure is proportional to mole fraction.

Then;

0.15 + 5.67 = 5.82.

Therefore, 5.67/ 5.82= 0.97.

Hence the vapor pressure of a solution = 0.97 × 23.76.

vapor pressure of a solution = 23.15 mmHg.

4 0
3 years ago
Read 2 more answers
I bet that outfit is made of Copper and Tellurium, because it is so ________.
Aleonysh [2.5K]

THE SYMBOLS!!!

CuTe

LOLOLOL

7 0
3 years ago
Read 2 more answers
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