Question

What mass of PCl5 will be produced from the given masses of both reactants? Express your answer to three significant figures and include the appropriate units.

Answer 1

69 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

P₄ + 10Cl₂ → 4PCl₅

How to calculate the number of moles ?

To calculate the number of moles used the formula

Number of moles = $\frac{\text{Given Mass}}{\text{Molar mass}}$

Number of moles of P₄ = $\frac{\text{Mass of}\ P_4}{\text{Molar mass of}\ P_4}$

                                       = $\frac{28\ g}{124\ g/mol}$

                                       = 0.225 mol

Number of moles of Cl₂ = $\frac{\text{Mass of}\ Cl_2}{\text{Molar mass of}\ Cl_2}$

                                        = $\frac{51\ g}{71\ g/mol}$

                                        = 0.831 mol

From the balanced chemical equation we can say that the ratio of P₄ and Cl₂ is 1 : 10.

Ratio of P₄: 0.2260: 1  = 0.2260

Ratio of Cl₂:  0.8310: 10 =  0.08310

Because ratio of Cl₂ ratio smaller than P₄ becomes the limiting reactants

So mole of PCl₅ is based on mole of Cl₂

From the coefficient of reaction:

mol PCl₅: mol Cl₂ = 4: 10

Mole of PCl₅ = $\frac{4}{10} \times 0.8310$

                     = 0.3324

Molar mass of PCl₅= 208.5

Mass of PCl₅ = mole × molar mass

Mass of PCl₅ = 0.3324 × 208.5

Mass of PCl₅ = 69 gram

Thus from the above conclusion we can say that 69 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.

Learn more about the Number of moles here: brainly.com/question/15356425

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Question: What mass of PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂ ?