The three types of catalyst are positive, negative and auto-catalytic. <span>A positive catalyst increases the activation energy which decreases the rate or speed of the reaction. A negative catalyst decreases the activation energy which increases the rate or speed of thee reaction. An auto-catalyst starts slows and the reaction continues itself based on the products formed.</span>
Answer:
8.59 g
2.25 g
Explanation:
According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-
Moles of Pb(OH)CL is


= 0.0385 mol
Mass of PbO needed is

After solving the above equation we will get
= 8.59 g
Mass of NaCL needed is

After solving the above equation we will get
= 2.25 g
Therefore we have applied the above formula.
Answer: AgNO3 is the limiting reactant.
Explanation:
1) Balanced chemical equation:
<span>Given: 2AgNO3 + NiCl2 → 2AgCl + Ni(NO3)2
2) Mole ratios:
2 mol AgNO3 : 1 mol NiCl2 : 2 mol AgCl : 1 mol Ni(NO3)2
3) Convert 0.847 g of AgNO3 to moles
n = mass in grams / molar mass
molar mass = sum of the masses of all the atoms in the molecular formula
molar mass of AgNO3 = 107.9 g/mol + 14.0 g/mol + 3*16.0 g/mol = 169.9 g/mol
n = 0.847 g / 169.9 g/mol = 0.00499 mol AgNO3
4) Convert 0.650 g of NiCl2 to moles
n = mass in grams / molar mass
molar mass NiCl2 = 58.7 g/mol + 2*35.5 g/mol = 129.7 g/mol
n = 0.650 g / 129.7 g/mol = 0.00501 mol NiCl2
5) Compare the theoretical mole ratio with the actual ratio:
Theoretical mole ratio: 2 mol AgNO3 / 1 mol NiCl2
Actual ratio: 0.00499 mol AgNO3 / 0.00501 mol Ni Cl2 ≈ 1:1
Therefore, the amount of AgNO3 is half the required amount need to react with all the NiCl2, which means that the AgNO3 will react completely and there will be an excess of NiCl2. The reactant that is consumed completely while the other is left, is the limiting reactan. This is, AgNO3 is the limiting reactant.</span>
Johnny has 69420 sperm cells, he busts 420 sperm cells. How much sperm is left??
Answer:
I’m not sure probably false
Explanation: