Answer:
The new pressure of the gas comes out to be 400 KPa.
Explanation:
Initial volume of gas = V = 
Initial pressure of gas = P = 120 KPa
Final volume of gas = V' = 
Assuming temperature to be kept constant.
Assuming final pressure of the gas to be P' KPa
New pressure of gas = 400 KPa
Answer:
The correct answer is that both molecular motion, pressure and temperature increase as volume reduces.
Explanation:
A reduction in volume changes the molecular motion, temperature and pressure of the system. When the volume of the container decreases, this causes the pressure to increase, the temperature to increase and the molecular motion to increase. This is because a liquid and a solid are incompressible, so by reducing the volume of a gas, the molecules increase their movement as the temperature of the system increases, which is due to the increased pressure applied to reduce the volume of the system.
Have a nice day!
Answer:
John Newlands
Explanation:
he established the law of octaves
1.64 L of sulfur dioxide (SO₂)
Explanation:
We have the following chemical reaction:
S (s) + O₂ (g) → SO₂ (g)
First we calculate the number of moles of sulfur (S):
number of moles = mass / molar weight
number of moles of sulfur = 2.35 / 32 = 0.0734 moles
Looking at the chemical reaction we see that 1 moles of sulfur (S) produces 1 moles of sulfur dioxide (SO₂), so 0.0734 moles of sulfur will produce 0.0734 moles of sulfur dioxide (SO₂).
To calculate the volume of sulfur dioxide (SO₂), assuming that the sulfur dioxide is behaving as an ideal gas and the we determine the gas volume under standard temperature and pressure conditions, we use the following formula:
number of moles = volume / 22.4 (L/mole)
volume = number of moles × 22.4
volume of SO₂ = 0.0734 × 22.4 = 1.64 L
Learn more about:
molar volume
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PS: I appreciate that you took the time and effort to write the chemical equation in a readable way. This makes the question to be very rare :D
