Answer:
The parent sine graph
has a range of -1 ≤ y ≤ 1
It crosses the x-axis x = 0° ± 180°n
The maximum points occur when x = 90° ± 360°n and y = 1
The minimum points occur when x = 270° ± 360°n and y = -1
The sketch the graph of function
we simply move the graph of
up 2 units.
So this means it will have a range of 1 ≤ y ≤ 3
It no longer crosses the x-axis.
The maximum points occur when x = 90° ± 360°n and y = 3
The minimum points occur when x = 270° ± 360°n and y = 1
<u>Attached diagram</u>
The parent function
is shown in grey (dashed line)
The function
is shown in red.
Answer:
After simplifying we get (x,y) as (1,3).
Step-by-step explanation:
Given:
,

We need to use elimination method to solve the and simplify the equations.
Solution;
Let
⇒ equation 1
Also Let
⇒ equation 2
Now by solving the equation we get;
first we will Add equation 2 from equation 1 we get;

Now Dividing both side by 5 using division property of equality we get;

Now Substituting the vale of x in equation 1 we get;

subtracting both side by 1 using subtraction property of equality we get;

Now Dividing both side by 7 using division property of equality we get;

Hence we can say that, After simplifying we get (x,y) as (1,3).
Answer:
D)
, 
Step-by-step explanation:
The blue boundary line has a y-intercept of 2 and a slope of 2.
It has equation : 
Since the boundary line is not solid and the lower half plane of this line is shaded, its inequality is

The blue boundary line passes through the origin and has slope
.
Its equation is 
Since the boundary line is not solid and the right half-plane is shaded, its inequality is 
The correct choice is D.
Answer:
Option d
Step-by-step explanation:
We need 2 fundamental data to solve this problem.
1.- Average number of clients attended in 1 hour.
2.- Time in which it is expected that a client will be attended.
They tell us that the average number of clients served in an hour is m = 8
They tell us to calculate the probability that the client will be seen in less than 15 minutes.
But the time t in the formula is given in hours.
Therefore we must write 15 minutes according to hours.
We know that
.
So:
.
Now we substitute in the formula
and
to find P.

Answer:
The area of a square with side length of 2 inches is 4 square inches.
The area of a circle with radius 1.2 inches is:

That is approximately 4.5 square inches.
Hence, the area of the square (4) is less than {<} that of the circle (4.5)!