Answer:
400 800 1200 1600 2000 is anwser
This is how you write 5.24 in expanded form 5+0.2+0.04
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
Answer:
$80,500
55,500 + 1,500t
Step-by-step explanation:
The question is an arithmetic progression series
Where,
a= first term
d= common difference
n= number of terms
a = $70,000
d= $1,500
n= 8 years
8th term = a + (n-1) d
= 70,000 + (8-1)1500
= 70,000 + 7(1500)
= 70,000 + 10,500
= $80,500
Jocelyn salary after 8 years is $80,500
Solve for when n = t
t th term = a + (n-1)d
= 70,000 + (t - 1)1500
= 70,000 + 1,500t - 1,500
= 55,500 + 1,500t
t th term = 55,500 + 1,500t
Answer:
Girls to boys = 1:2
Girls to students = 1:3
Boys to students = 2:3
Step-by-step explanation:
So, let's subtract the number of girls from the number of students in the class:
60 - 20 = 40
This means that for every 20 girls there are 40 boys in the ratio of girls to boys:
20:40
This can be simplified down by factoring, here we can divide by 20:
(20 ÷ 20) : (40 ÷ 20)
1:2
So the ratio of girls to boys is 1:2
The ratio of boys to students can be calculated via:
40:60
This can be simplified by dividing by 20 again:
(40 ÷ 20) : (60 ÷ 20)
2:3
So the ratio of boys to students is 2:3
The ratio of girls to students can be put in a ratio of:
20 : 60
This can be simplified down by dividing by 20:
(20 ÷ 20) : (60 ÷ 20)
1:3
So the ratio of girls to students is 1:3
Hope this helps!
