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IgorLugansk [536]
3 years ago
10

LEIM deposits some money in an account which pays 5% simple interest per year, and twice that amount in an account paying 4% sim

ple interest per year. If he collects $533.00 in interest after one year, how much did he deposit in the account that has a 5% rate?
Mathematics
2 answers:
Tamiku [17]3 years ago
8 0

Answer:

266.5

Step-by-step explanation:

$533.00* 5%=266.5

olga nikolaevna [1]3 years ago
7 0
The answer is 266.5 hope this helps
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It is A. I took the test,

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A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin
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Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

T_1cos\theta_1-T_2cos\theta_2=0           (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

T_1sin\theta_1+T_2sin\theta_2-W=0               (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2

Then, you sum the equations:

T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2        (3)

Next, you use the following identity:

sin^2\theta+cos^2\theta=1

and you obtain in the equation (3):

T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°

With this values you can calculate the value of the another angle, by using the equation (1):

\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

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Answer:

D. rectangles

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Question 8.8. Which figure is not completely constructed from polygons? (Points : 5)
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A bag contains 11 blocks numbered from 1 to 11. Two blocks are selected from the bag at the same time. (order does not matter) L
melamori03 [73]

Answer:

(A) n(Eᶜ)=40

Step-by-step explanation:

The Sample Space for is given as:

(1,2),(1,3),(1,4),(1,5),(1,6),(1,7),(1,8),(1,9),(1,10),(1,11)

(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)

(3,4),(3,5),(3,6),(3,7),(3,8),(3,9),(3,10),(3,11)

(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)

(5,6),(5,7),(5,8),(5,9),(5,10),(5,11)

(6,7),(6,8),(6,9),(6,10),(6,11)

(7,8),(7,9),(7,10),(7,11)

(8,9),(8,10),(8,11)

(9,10),(9,11)

(10,11)

n(S)=55

Event E is the Event that the two numbers are odd.

Therefore: Complement of E will be the event that any of the  two numbers is even.

The Sample Space of the complement of E is:

(1,2),(1,4),(1,6),(1,8),(1,10)\\(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)\\(3,4),(3,6),(3,8),(3,10)\\(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)\\(5,6),(5,8),(5,10)\\(6,7),(6,8),(6,9),(6,10),(6,11)\\(7,8),(7,10)\\(8,9),(8,10),(8,11)\\(9,10)\\(10,11)\\

Therefore:

n(Eᶜ)=40

5 0
4 years ago
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