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3 years ago

Please help me! WILL MARK BRAINLIEST. Thanks!

Mathematics

1 answer:

galben [10]3 years ago

5 0

Answer:

For the first table: (0, 10) (1, 15) (2, 20) (3, 25) (4, 30)

For the second table: (-2, 1.04) (-1, 1.2) (0, 2) (1, 6) (2, 26)

For the third table: (-2, 10) (-1, 0) (-1/2, -5/4) (1, 10)

Step-by-step explanation:

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Store B

Step-by-step explanation:

Store A

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22.00-4.40=17.6

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3 years ago

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2 years ago

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Step-by-step explanation:

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2 years ago

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Ryan has 96 business cards. He buys 225 more cards. He hands out 248 cards at the conference. How many cards does Ryan have left

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Step-by-step explanation:

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2 years ago

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In a random sample of 60 computers, the mean repair cost was $150. Assume the population standard deviation is $36. Construct a

yaroslaw [1]

Answer:

The 95% confidence interval for the population mean is between $140.89 and $159.11

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. So

$M = 1.96\frac{36}{\sqrt{60}} = 9.11$

The lower end of the interval is the sample mean subtracted by M. So it is $150 - $9.11 = $140.89

The upper end of the interval is the sample mean added to M. So it is $150 + $9.11 = $159.11

The 95% confidence interval for the population mean is between $140.89 and $159.11

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2 years ago