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Arisa [49]
3 years ago
8

Quadrilateral ABCD is inscribed in the circle. Which sentence is true?

Mathematics
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

A) A and B are supplementary

Step-by-step explanation:

we know that

For any inscribed  quadrilateral in the circle , opposite angles will be supplementary

so

In this problem

Angle A and Angle B are supplementary angles

m\angle A+m\angle C=180^o

Angle B and Angle D are supplementary angles

m\angle B+m\angle D=180^o

therefore

<u><em>The sentences that are true </em></u>

A) A and B are supplementary

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Which ordered pair is included in the solution set to the following system?
Nataliya [291]

The ordered pair is included in the solution set to the following system is (0,2)

<h3>Set of inequalities</h3>

Given the set of inequalities

y > x2 + 1

y < x2 – x + 1

Equate both expressions to have:

x^2 + 1 = x^2 - x +1

1 = -x + 1

x = 0

Substitute x = 0 into any of the function

y = x^2 + 1

y = 1

This shows that the ordered pair is included in the solution set to the following system is (0,2)

Learn more on inequality here: brainly.com/question/24372553

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7 0
2 years ago
Give the prime algebraic factorization: 15a2b = _____
Nookie1986 [14]

Answer:

3a5a2b

Step-by-step explanation:

You can prime factorize 15: 3 x 5

7 0
3 years ago
Find the area of the parallelogram.
Ksivusya [100]
Area=14cm×6cm=84 cm²
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5 0
3 years ago
Read 2 more answers
8x55= hmmm what is this summ
Evgen [1.6K]

Answer:

440

Step-by-step explanation:

55x8. 8x5=40 carry the 4. 8x5=40+4=44 so it is 440

5 0
3 years ago
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John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
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