Find the GCD (or HCF) of numerator and denominator
GCD of 7 and 9 is 1Divide both the numerator and denominator by the GCD
(7/1)/(9/1)Reduced fraction: 7/9
<span>if a = 2x and b = 1
(2x)</span>³+1³ = (2x+1)(4x²-2x+1)
I hope this helps
29-4 = 25
29+4 = 33
So, from 25 to 33 minutes.
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I am going to explain this using the substitution method, considering it appears to be the best in this situation.
We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:
3x+20=x^2+2x
Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you
x+20=x^2
Now, we take the square root of both sides to get
rad(x+20)=x
Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes
2rad(x+5)
This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
