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Musya8 [376]
3 years ago
7

In the year 1987, an investment was worth $29,800. In the year 1997, this

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer:

a) 46.98%

b) increasing rate of change

Step-by-step explanation:

In year 1987, investment worth $29800

In year 1997, investment worth $43800

Rate of change = 1997investment - 1987investment / 1987investment × 100

Rate of change = 43800 - 29800/29800 × 100

= 14000/29800 × 100

= 0.46979 × 100

= 46.98%

Therefore, the rate of change of the investment during the time period is 46.98%.

b) The rate of change of the investment is increasing. This is as a result of the following reasons. First, the value of rate of change is positive. Second, there is no value for rate of change for period before the time period so we cannot compare rate of change.

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3 years ago
Solve the system of equations 2x-2y=-14 and 3x-y=-1 by combining the equations.
Veseljchak [2.6K]

The solution to the system of equations is x = 3 and y = 10

<h3>How to solve the equations?</h3>

The system is given as:

2x-2y=-14

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So, we have:

1(2x-2y=-14)

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Read more about system of equations at:

brainly.com/question/12895249

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1 year ago
Solve: /3=46<br><br> x/3 is a fractions
den301095 [7]

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3 years ago
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