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Musya8 [376]
4 years ago
7

In the year 1987, an investment was worth $29,800. In the year 1997, this

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
8 0

Answer:

a) 46.98%

b) increasing rate of change

Step-by-step explanation:

In year 1987, investment worth $29800

In year 1997, investment worth $43800

Rate of change = 1997investment - 1987investment / 1987investment × 100

Rate of change = 43800 - 29800/29800 × 100

= 14000/29800 × 100

= 0.46979 × 100

= 46.98%

Therefore, the rate of change of the investment during the time period is 46.98%.

b) The rate of change of the investment is increasing. This is as a result of the following reasons. First, the value of rate of change is positive. Second, there is no value for rate of change for period before the time period so we cannot compare rate of change.

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A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
4 years ago
Sandra has ribbons that are 2/6 meter 3/4meter and 4/9 meter long .She needs to use the ribbon longer than 2/3meter to make a bo
timurjin [86]

Answer:

3/4 meter

Step-by-step explanation:

Need Common denominators to compare size

2/6  3/4  4/9     which is longer than 2/3?

2/6 compared to 2/3.  2/6 = 2/6 and 2/3 = 4/6.  

2/6 < 2/3 so 2/6 is too short

3/4 compared to 2/3   3/4 = 9/12  and 2/3 =  8/12

3/4 > 2/3 so 3/4 is longer than 2/3

4/9 compared to 2/3  4/9 = 4/9 and 2/3 = 6/9

4/9 < 2/3 so 4/9 is too short

6 0
3 years ago
Read 2 more answers
How many batches of trail mix can Eric make with 16 cups of peanuts, 15 cups of raisins, and 8 cups of walnuts?​
vazorg [7]

Answer:27

Step-by-step explanation:

Are you in middle school

5 0
3 years ago
Solve for y in x+0.25y=1.5
IRISSAK [1]

Answer:

Y=-4x+6

Step-by-step explanation:

Step 1: Add -x to both sides.

X+0.25y+-x=1.5+-x

0.25y=-x+1.5

Step 2: Divide both sides by 0.25.

0.25y/0.25=-x+1.5/0.25

Y=-4x+6

Hope I helped

5 0
3 years ago
Can someone help me out?
Lera25 [3.4K]

Answer:

so basically

the area of the square; (5cm)^2 = 25cm^5

the area of the triangle; (4cm.5cm)/2 = 10cm^2

which means that r = √25cm^2/10cm^2 = √25/10 cm^2 or √10/25 cm^2

english is not my first language so i do not know what combined means but if u explain a little more i will try to help u

-> ok edit edit;

1cm/5in. = r

5cm => 25in.

z^2= area of a square so

25in.25in= 625 in^2

4cm => 20in.

5cm => 25in.

h.b/2 = area of a triangle so

20in.25in./2 = 250in.^2

250in.^2 + 625in.^2 = 875in.^2

so answer B

5 0
3 years ago
Read 2 more answers
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