Answer:
9 1/6 miles
Step-by-step explanation:
Add the mixed number by the improper fraction.
1 + 1/3 + 35/6
Solve the fractions first.
In order to have both of the fractions have the same denominator, find the Least Common Multiple of both of the fractions.
1/3 = 2/6
2/6 + 35/6 = 37/6
Turn the improper fraction into a mixed number by dividing the the numerator by the denominator. When you get your quotient, use the remainder as the new numerator over the denominator.
37/6 = 6 1/6
Now, add the 1.
6 1/6 + 1 = 7 1/6
Now, add the 2 miles that Carol walked on Wednesday.
7 1/6 + 2 = 9 1/6
So, Carol walked about 9 1/6 miles on Monday, Tuesday, and Wednesday all together.
Answer:
x = 0 or 1 or -2
Step-by-step explanation:
x(x^3-3x+2)=0
x(x-1)^2 * (x+2)0
so x = 0 or 1 or -2
there is no imaginary solutions
The dimension of the document is 35 inches by 40 inches.
It is redrawn at a scale of 1 1/2 or 3/2 or 1.5
The dimension will be:
35 * 1.5 = 52.5 in
40 * 1.5 = 60 in
Then redrawn again at 1/4 or 0.25
52.5 * 0.25 = 13.125 in
60 * 0.25 = 15 in
So the final dimensions of the drawing is 13.125 in by 15 in
Answer:
Step-by-step explanation:
N= 100+n(10)
Answer:
D) a reflection over the line x = 0 followed by a reflection over the line y = 0.
Step-by-step explanation:
In this problem, the original figure is in quadrant I (1) and the second image is in quadrant III (3). In order for the figure to make this transition and be 'flipped' into the opposite direction of the original figure, a reflection would have to take place. If triangle 'A' is reflected over the line y = x or y = -x, the orientation of the triangle would stay the same, meaning the point of the triangle would still face upward. If you reflect over the line x = 0 and then again over the line x = 0 (as in C), your triangle would be in the same spot. However, if you reflect triangle 'A' over x = 0, you would get a 'flipped image' into quadrant 4 and the orientation of the triangle would face downward. Following this reflection by another reflection over the line y=0 would give you the mirror image in quadrant III (3). So, D is the correct sequence of reflections.
