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Alecsey [184]
1 year ago
7

Tim Hortons is hiring and offers $200 every week plus $5 per hour. McDonalds offers $300 every week plus $2 per hour. State the

conditions under which Tim Hortons is the better employer.
Mathematics
1 answer:
Bogdan [553]1 year ago
8 0

Answer: After working for 33 \frac{1}{3} hours a week

Step-by-step explanation:

     Let us write equations to represent these two places. Let x be hours worked and y be money earned.

   Tim Hortons:

$200 + $5x = y

    McDonalds:

$300 + $2x = y

    Now, to find the conditions of which Tim Hortons is the better employer (on the basis of money earned) we must find the interval that Tim Hortons pays more. This can be found by setting up another equation, or by graphing. I have shown both. <em>See attached for the graph</em>.

$200 + $5x > $300 + $2x

$5x > $100 + $2x

$3x > $100

x > \frac{100}{3}

x > 33.3334

    Tim Hortons is the better employer after an employee has worked for 33 \frac{1}{3} hours a week.

<em>Read more about </em><em>this question</em><em> here:</em>

<em>brainly.com/question/24206551</em>

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Find 6% of $5.65 and round the product to the nearest cent.
Leviafan [203]

Answer:

$0.34

Step-by-step explanation:

a = p*w

a = .06*5.65

a = 0.339

rounded = 0.34

hope this helps :)

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3 years ago
Which of the following is(are) true? I. The mean of a population depends on the particular sample chosen. II. The standard devia
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Answer:

II and III

Step-by-step explanation:

From statement II in the question, it is true that the standard deviations of two different samples from the same population may be the same. The population standard deviation is a fixed value calculated from every individual in the population.  A sample standard deviation is calculated from only some of the individuals in a population.

Also from statement III, it is true that statistical inferences can be used to draw conclusions about the populations based on sample data. The mean of a population does not necessarily depends on the particular sample chosen. Therefore statement I is false.  

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2 years ago
Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B
Oksanka [162]

This is not the question, the correct question is:

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D: Scores below the top 83% and above the bottom 7% F: Bottom 7% of scores.

Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B grade. Round your answers to the nearest whole number, if necessary.

Answer:  The numerical limits for grade B is 81 and 92

Step-by-step explanation:

Given that

mean Ж = 79

Standard deviation S = 8.4

B: Scores below the top 6% and above the bottom 59%

To find the numerical value for Grade B

Below the top bottom 6% ( 0.06) is

p ( X < Ж ) = 1 - 0.06

p ( X < Ж ) = 0.94

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.94

(X - 79) / 8.4 = 1.5548 ( from normal distribution table )

X - 79 = 13.0603

X = 13.0603 + 79

X = 92.06 ≈ 92 ( nearest whole number)

Above bottom 59% ( 0.59) is

p ( X < Ж ) = 0.59

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.59

(X - 79) / 8.4 = 0.2275 ( from normal distribution table )

X - 79 = 1.9114

X = 1.9114 + 79

X = 80.91 ≈ 81 ( nearest whole number)

So the numerical limits for grade B is 81 and 92

3 0
3 years ago
7 1/4 × 2²+(8 1/2-2)÷3<br>giving brainliest
lawyer [7]

Answer:

187/6

Step-by-step explanation:

Simplify the following:

(7 + 1/4) 2^2 + (8 + 1/2 - 2)/3

2^2 = 4:

(7 + 1/4) 4 + (8 + 1/2 - 2)/3

Put 7 + 1/4 over the common denominator 4. 7 + 1/4 = (4×7)/4 + 1/4:

(4×7)/4 + 1/4 4 + (8 + 1/2 - 2)/3

4×7 = 28:

(28/4 + 1/4) 4 + (8 + 1/2 - 2)/3

28/4 + 1/4 = (28 + 1)/4:

(28 + 1)/4×4 + (8 + 1/2 - 2)/3

28 + 1 = 29:

29/4×4 + (8 + 1/2 - 2)/3

29/4×4 = (29×4)/4:

(29×4)/4 + (8 + 1/2 - 2)/3

(29×4)/4 = 4/4×29 = 29:

29 + (8 + 1/2 - 2)/3

Put 8 + 1/2 - 2 over the common denominator 2. 8 + 1/2 - 2 = (2×8)/2 + 1/2 + (2 (-2))/2:

29 + ((2×8)/2 + 1/2 + (2 (-2))/2)/3

2×8 = 16:

29 + (16/2 + 1/2 + (2 (-2))/2)/3

2 (-2) = -4:

29 + (16/2 + 1/2 + (-4)/2)/3

16/2 + 1/2 - 4/2 = (16 + 1 - 4)/2:

29 + ((16 + 1 - 4)/2)/3

16 + 1 = 17:

29 + ((17 - 4)/2)/3

| 1 | 7

- | | 4

| 1 | 3:

29 + (13/2)/3

13/2×1/3 = 13/(2×3):

29 + 13/(2×3)

2×3 = 6:

29 + 13/6

Put 29 + 13/6 over the common denominator 6. 29 + 13/6 = (6×29)/6 + 13/6:

(6×29)/6 + 13/6

6×29 = 174:

174/6 + 13/6

174/6 + 13/6 = (174 + 13)/6:

(174 + 13)/6

| 1 | 7 | 4

+ | | 1 | 3

| 1 | 8 | 7:

Answer: 187/6

3 0
2 years ago
Read 2 more answers
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