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3 years ago

-4 plus what number is 04

Mathematics

2 answers:

o-na [289]3 years ago

5 0

Answer:

Set up an equation

-4+x=4 Add 4 to each side

x=8

-4 plus eight is 4

boyakko [2]3 years ago

4 0

Answer:

Step-by-step explanation:

-4 +8 = 4

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Answer:

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2 years ago

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Multiply (4+I)(1-5i)

Svetllana [295]

The rule to remember for this problem is: i^2 = -1
(4 + i)(1 - 5i)
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3 years ago

Solve the following recurrence relation: <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

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2 years ago

Solve the following quadratic equation for all value of c i'm simplest form 5(x-2)^2=20

xz_007 [3.2K]

Answer:

x=-2 and x=0

Step-by-step explanation:

5(x-2)^2 = 20; divide by 5 both sides

(x-2)^2 = 4; take the square root of both sides

(x-2) = ±2, now set it equal to positive 2 and negative 2

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AND

x-2 = -2

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3 years ago

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