Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
Answer:
The answer is "Option C"
Step-by-step explanation:
The choices were missing in the question, which is defined in the attached file please find it.
To attend university, Chole should pay the cost of a room and board each semester. Even though the Chole will not be in college, she will still have a room as well as a board and continue living.
- If she will not attend college, it also has to equate rooms and board costs per six months since increase towards the room or board charges.
- If there's an increase in rooms and boarding costs because she did not understand below the rise in their school fees, therefore the financial cost reduces that desire of she attend.
Answer:

The maximum width must be 
Step-by-step explanation:
Let
L ----> the length of the rectangular pool
W ---> The width of the rectangular pool
we know that

so
----> inequality A
we have

substitute the value of L in the inequality A

simplify



The maximum width must be 
Answer:
51/40
Step-by-step explanation:
2/5+7/8
(2*8/5*8)+(7*5/5*8)
16/40+35/40
=>51/40