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3 years ago

A pure substance that is made of only one kind of atom is called _________.

2 answers:

6 0

A pure substance that is made of only one kind of atom is called an element.

An element is a pure substance, which means it is made up of only ONE kind of atom.

nexus9112 [7]3 years ago

6 0

A pure substance that is made of only one kind of atom is called an element I hope this help:) have a nice day

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Please answer this for me

Nezavi [6.7K]

$\sqrt{3$ Answer:

Step-by-step explanation:

take 45 degree as reference angle

using sin rule

sin 45=opposite/hypotenuse

1/ $\sqrt{2$ =x/26

x=26/ $\sqrt{2$

x=13 $\sqrt{2$

x=18.4

4 0

2 years ago

Please help me out with equations in math! Its a starr review!

Alexeev081 [22]

Answer:

Step-by-step explanation:

Multiply -3 by 6.5 and you'll get your answer :)

I hope I helped!

4 0

2 years ago

Find the slope of the line passing through the points (1, -5) and (4, 1).

wlad13 [49]

The slope of line passing through the points (1, -5) and (4, 1) is 24

Step-by-step explanation:

Slope is the steepness of a line passing through given points

Given points are:

(x1,y1) = (1, -5)

(x2,y2) = (4,1)

The slope is denoted by m. The formula for slope is:

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{1-(-5)}{4-1}\\=\frac{6}{3}\\=2$

The slope of line passing through the points (1, -5) and (4, 1) is 2

Keywords: Slope, Calculation of slope

Learn more about slope at:

#LearnwithBrainly

7 0

2 years ago

PLEASE! WILL GIVE METAL AND FAN.

Pani-rosa [81]

20000*0.45 = 9000 in the bond
20000*0.15 = 3000 in the CD
20000*0.20 = 4000 in stocks
20000*0.029 = 580 in savings

A=9000(1 + 4.35%)^3 = 10,226.33
A=3000(1 + 2.90%)^3 = 3,268.64
A=4000 (1 + 8%) x (1 - 4%) x (1 + 6%) = 4,396.03
A=580(1 + 4.35%)^3 = 4,545.04
Total value = 22,436.04
Gain = 22,436.04 - 20,000 = 2,436.04

6 0

3 years ago

Read 2 more answers

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago