Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Answer:
148.91
Step-by-step explanation:
hope it helps<333
The right answer is Option A: pq(p+1)(p-1)
Step-by-step explanation:
Given expression is
Taking pq common from the expression
We know that;
Here;
Therefore;
Thus, the expression becomes
The linear factors of are pq(p+1)(p-1)
The right answer is Option A: pq(p+1)(p-1)
Keywords: linear factors, common terms
Learn more about linear factors at:
#LearnwithBrainly
Answer:
Multiply (400 + 20 + 3) x 10000
Add 4 zeros to the end of 423
Step-by-step explanation:
423 x 10,000 = Adding the amount of zero’s in 10000 to 423