Question

Please help! Fred mixes a solution using two types of solutions: 0.60 liters containing 10% alcohol and 0.40 liters containing 35% alcohol.
What is the alcohol concentration of the mixed solution?

Answer 1

Answer:

20%

Step-by-step explanation:

Total Litres in mixture=(0.60+0.4)=1 Litre

alcohol in first portion:=0.10(0.60)=0.06 Litres

alcohol in second portion:=0.35(0.40)=0.14 Litres

Total alcohol in mixture = 0.06 +0.14 = 0.20

% of alcohol in mixture:

                                          $\frac{0.2}{1} (100) = 20%$%

Answer 2

Answer: 20%. Based on the given conditions, formulate:: 35% * 0.4 + 0.6 * 10% / 0.4 + 0.6Calculate the product