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MrRissso [65]
3 years ago
11

Can someone help me pls thanks

Mathematics
1 answer:
allsm [11]3 years ago
8 0

Answer:

x = 1/2QN^2

Step-by-step explanation:

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A cube is packed with decorative pebbles. If the cube has a side length of 2 inches, and each pebble weighs on average 0.5 lb pe
kow [346]

We can solve this problem by first solving for the total volume of the cube. The formula for volume of cube is given as:

V cube = s^3

Where s is the length of one side which is equivalent to 2 inches. Therefore:

V cube = (2 inches)^3

V cube = 8 cubic inch

 

Assuming that all the pebble fills the cube without any spaces, then the total weight of the pebbles in the cube would simply be:

Total weight = 0.5 lb per cubic inch * 8 cubic inch

Total weight = 4 lb

 

Therefore, the total weight of the pebbles in the cube is <u>4 lbs</u>.

5 0
3 years ago
What would have to be done to put 3x (2x - 7) =9 in standard form? Group of answer choices
Artemon [7]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Please help!! And show work please! I'll give brainlist..!
mr_godi [17]
What you put is correct because two negatives make a positive so it would be 5 + 7 making it the greatest value
6 0
3 years ago
Um- help-.. please don’t comment if you don’t know
IRISSAK [1]

Answer:

Each point does NOT ALWAYS give the same amount of tickets.

11 point would most likely give 90 tickets.

Step-by-step explanation:

2 points give 18 tickets = 9 tickets per point

3 points give 27 tickets = 9 tickets per point

9 points give 72 tickets = 8 tickets per point

You can add the 2 point value with the 9 point values to find out many point it takes to get to 90 tickets.

18(2 tickets) + 72(9 tickets) = 90(11 tickets)

3 0
3 years ago
Read 2 more answers
Please help me find X
Zanzabum

Answer:

  x = 2

Step-by-step explanation:

The product of distances from the intersection of secants to the near and far intersections with the circle are the same. For a tangent, the near and far points of intersection with the circle are the same. This relation tells us ...

  (2√3)(2√3) = x(x +4)

  12 = x² +4x

  16 = x² +4x +4 . . . . . add the square of half the x-coefficient to complete the square

  4² = (x +2)² . . . . . . . . write as squares

  4 = x +2 . . . . . . . . . . positive square root

  2 = x . . . . . . . . . . . . . subtract 2

_____

<em>Alternate solution</em>

If you believe x to be an integer, you can look for factors of 12 that differ by 4.

  12 = 1×12 = 2×6 = 3×4

The factors 2 and 6 differ by 4, so x=2 and x+4=6.

6 0
3 years ago
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