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3 years ago

Which equation represents a linear function? (1 point)

Mathematics

1 answer:

Elan Coil [88]3 years ago

4 0

Answer:

Option D

Step-by-step explanation:

' y = 4x − 1' would graph as a straight line. Therefore, it is a linear equation.

Liner equations are graphed as a straight line, while nonlinear equations are not.

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Which of the following solutions solves the system?

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2 years ago

Use the following rules to graph and label the ordered pairs on a coordinate grid with at least 4 points on the coordinate plane

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${ - a}^{3} . {b}^{3} = ( { - a \times b})^{3} = ( { - ab})^{3} \\$

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2 years ago

A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st

SpyIntel [72]

Answer: $15.3\pm0.198$

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval $(\mu)$ is given by :-

$\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

, where n is the sample size

$s$ = sample standard deviation.

$\overline{x}$ = Sample mean

$z_{\alpha/2}$ = Two tailed z-value for significance level of $\alpha$ .

Given : Confidence level = 95% = 0.95

Significance level = $\alpha=1-0.95=0.05$

$s= 1.6$

$\overline{x}=15.3$

sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , $\sigma=1.6$

By standard normal distribution table ,

Two tailed z-value for Significance level of 0.05 :

$z_{\alpha/2}=z_{0.025}=1.96$

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

$15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)$

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

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3 years ago

The number that appears in the middle of an organized set of data from least to greatest

kvv77 [185]

The answer is median

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3 years ago

Read 2 more answers