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nevsk [136]
3 years ago
10

Which equation represents a linear function? (1 point)

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

Answer:

Option D

Step-by-step explanation:

' y = 4x − 1'  would graph as a straight line. Therefore, it is a linear equation.

Liner equations are graphed as a straight line, while nonlinear equations are not.

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Step-by-step explanation:

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Rewrite the product as a power:<br> <img src="https://tex.z-dn.net/?f=%28-a%29%5E%7B3%7D%20b%5E%7B3%7D" id="TexFormula1" title="
anastassius [24]

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{ - a}^{3} . {b}^{3}  = ( { - a \times b})^{3}  = ( { - ab})^{3}  \\

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4 0
2 years ago
A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st
SpyIntel [72]

Answer:  15.3\pm0.198

OR

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval(\mu) is given by :-

\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

, where n is the sample size

s = sample standard deviation.

\overline{x}= Sample mean

z_{\alpha/2} = Two tailed z-value for significance level of \alpha .

Given : Confidence level = 95% = 0.95

Significance level = \alpha=1-0.95=0.05

s= 1.6

\overline{x}=15.3

sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , \sigma=1.6

By standard normal  distribution table ,

Two tailed z-value for Significance level of 0.05 :

z_{\alpha/2}=z_{0.025}=1.96

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

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3 years ago
The number that appears in the middle of an organized set of data from least to greatest
kvv77 [185]
The answer is median
5 0
3 years ago
Read 2 more answers
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