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2 years ago

Please help asappp!!!

Mathematics

2 answers:

Semmy [17]2 years ago

8 0

Answer:

Slope = 0

Equation: y = 2

Step-by-step explanation:

PQ is parallel to x-axis. Slope of the line parallel to x-axis = 0.

Slope of diagonal PQ = 0

Equation of line parallel to x-axis : y = a

Equation of diagonal PQ: y = 2 or y -2 = 0

arsen [322]2 years ago

5 0

Answer:

y = 2

Step-by-step explanation:

Since it's a flat line, the slope is 0.

Since all of the points have a y-value of 2, the equation is y = 2.

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Please answer both questions and show all work with explanations :) thank you soo much...

torisob [31]

Answer:

1) 109 cm

2) 120 in²

Step-by-step explanation:

A rectangle is a quadrilateral with opposite sides the same length and four (4) right angles. The diagonal, together with two adjacent sides, forms a right triangle. The relationship between side lengths and the diagonal length is given by the Pythagorean theorem. If sides are "a" and "b" and the diagonal is "c", that theorem tells you ...

... c² = a² + b²

1) c² = (60 cm)² + (91 cm)² = 11881 cm²

... c = √11881 cm = 109 cm

2) The perimeter is double the sum of adjacent side lengths, so ...

... 2(a+b) = 46 in

... a + b = 23 in . . . . . divide by 2

The Pythagorean theorem tells you

... a² + b² = (17 in)²

Squaring the equation from the perimeter relation gives ...

... (a + b)² = (23 in)² = a² + 2ab + b²

Subtracting a² + b², we have

... (a² +2ab +b²) - (a² + b²) = (23 in)² -(17 in)²

... 2ab = (529 -289) in² = 240 in² . . . . . simplify

... 240 in²/2 = ab = 120 in² . . . . . area is the product of length and width

_____

We could solve the two equations for a and b to find that there are two possible solutions: (a, b) = (8, 15) or (15, 8). Either way, ab = 8·15 = 120.

7 0

3 years ago

What is the value of x, 6x +2=180

tester [92]

Answer: $x=\frac{89}{3}$ or $26\frac{2}{3}$

$\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\6x+2-2=180-2\\6x=178$

$\mathrm{Divide\:both\:sides\:by\:}6\\\frac{6x}{6}=\frac{178}{6}\\$

$x=\frac{89}{3}$

<em>Hope this helps and have a great day!!!</em>

7 0

3 years ago

Read 2 more answers

What is the answer to this question

ASHA 777 [7]

Round 5.49 down to 5.00
Round 10.98 to 11.00
20.00-5.00-11.00=4.00
the answer would be a.

8 0

3 years ago

(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa

mr Goodwill [35]

Answer:

a) $\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

b) $P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform $Y\sim Unif(A,B)$ . And the density function would be given by:

$f(x) =\frac{1}{B-A} , A$

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

$P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}$

And we can find the probability desired like this:

$P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)$

And from the cumulative distribution function of X ficen by $F(X)\frac{X-A}{B-A}$ we got:

$\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

Part b

For this case we assume that $X\sim Gamma (2,1)$

On this case we assume that $\alpha=2, \beta= 1$

The density function for the Gamma distribution is given by:

$P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}$

And on this case we can find the probability using the complement rule like this:

$P(X>1) = 1-P(X\leq 1)=0.736$

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

$P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

6 0

3 years ago

Students in 10th and 11th grade were asked whether they have a job. The raw data was converted to relative frequencies and recor

Step2247 [10]

Option A is correct. 0.14 represents that if a student is a 10th grader, there is a 14% chance he or she has a job.

it is given that there is a column with 4 column and 3 rows.

<h3>what is a conditional relative frequency table?</h3>

it is a special type of frequency table that shows relationships between two categories.

from the attached table it is clear that 0.14 is the probability of getting a job if a student is a 10th grader,

option B is incorrect, stating there is a 14% chance a student is a 10th grader if he/she has had a job since we do not know the number of students.

option C is also incorrect stating that 14% of the students surveyed are 10th graders who have a job since we do not know the total number of students.

option D is also incorrect because we do not know the number of students.

therefore, option A is correct. 0.14 represents that if a student is a 10th grader, there is a 14% chance he or she has a job.

to get more about conditional relative frequency-related problems, refer to the link,

brainly.com/question/22728236

3 0

2 years ago