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Savatey [412]
2 years ago
6

Jeremy earns extra money selling concessions during school sports events. On Thursday, he spent $126.78 at the local whole sale

store for concession supplies. His concession sales at two weekend games were $345.26 and $248.24. After taking into account his expenses, how much money did Jeremy earn?
I need your help, thank you in advance!
Mathematics
2 answers:
RideAnS [48]2 years ago
3 0

Answer:

I think Jeremy  earned $609.118 because you have to add

$126.78+$248.24+$345.26=$609.118

Step-by-step explanation:

hope this helps if it is wrong let me know have a blessed day

Harlamova29_29 [7]2 years ago
3 0

Answer:

John Copeland sells tennis equipment. He is guaranteed a minimum salary of $1,500 a month plus 5.75% of his total sales.what is the correct answer

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a university is comparing the grade point averages of biology majors with grade point averages of engineering majors. the univer
Ronch [10]

Answer:

H0 : μEng = μBio

H1: μEng ≠ μBio

Step-by-step explanation:

μEng = Engineering average gpa

μBio = Biology average gpa

To test for difference between two sample means , in this case grade point average of biology majors and Engineering major.

Null hypothesis is the initial truth, which is that ; there is no difference in the mean grade point average of both biology and engineering majors

H0 : μEng = μBio

The Alternative hypothesis is the opposite of the null, which is stated has ; there is difference between the average GPA of both Engineering and Biology majors

H1: μEng ≠ μBio

7 0
3 years ago
I don’t know what the answer to this question is , help
ipn [44]

Answer:

(4, 0)

Step-by-step explanation:

given the 2 equations

y = x - 4 → (1)

- 4x - 6y = - 16 → (2)

substitute y = x - 4 into (2)

- 4x - 6(x - 4) = - 16

- 4x - 6x + 24 = - 16

- 10x + 24 = - 16 ( subtract 24 from both sides )

- 10x = - 40 ( divide both sides by - 10 )

x = 4

substitute x = 4 into (1) for corresponding value of y

y = 4 - 4 = 0

solution is (4, 0)

3 0
3 years ago
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
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3 years ago
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