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Rama09 [41]
2 years ago
7

Can someone help me please?

Chemistry
1 answer:
mafiozo [28]2 years ago
7 0

Answer:

3 moles Al2O3

Explanation:

See attached image.

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Answer: E
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What are the coefficients that would balance this equation? ___ HCL+___ NaOH-___ NaCl+____ H20
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It's already balanced as the equation has the same number of atoms on both left and right side

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Enter the condensed electron configuration for cu4+.express your answer in condensed form, in order of increasing orbital energy
Marysya12 [62]
Electronic Configuration of Cu⁴⁺ is written using these two steps;

Step I:
          Write the Electronic Configuration of Copper (Cu).

As Atomic Number of Cu = 29
So,
                             1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹

Rearranging it in order of increasing orbital energy,

                             1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
                            Cu  =   [Ar] 4s¹, 3d¹⁰

Step II:
            Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
                            Cu⁴⁺  =   [Ar] 3d⁷
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4 years ago
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What is the chemistry of super glue
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2 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro
MAVERICK [17]

<u>Answer:</u> The percent yield of water is 46.9 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For sulfuric acid:</u>

Given mass of sulfuric acid = 72.6 g    (Assuming)

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol

  • <u>For NaOH:</u>

Given mass of NaOH = 77 g      (Assuming)

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{77g}{40g/mol}=1.925mol

The chemical equation for the reaction of sulfuric acid and sodium hydroxide follows:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

0.741 moles of sulfuric acid will react with = \frac{2}{1}\times 0.741=1.482mol of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of water

0.741 moles of sulfuric acid will react with = \frac{2}{1}\times 0.741=1.482mol of water

  • Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.67g

  • To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 12.5 g  (Assuming)

Theoretical yield of water = 26.67 g

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{12.5g}{26.67g}\times 100\\\\\% \text{yield of water}=46.9\%

Hence, the percent yield of water is 46.9 %

3 0
3 years ago
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