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3 years ago

Would kg,ml, or cm signify a measurement of weight?

Chemistry

2 answers:

In-s [12.5K]3 years ago

7 0

Kilograms (kg) would signify a measurement of weight.

Why? Because milliliters (ml) is the measurement of the capacity of a liquid. Centimeters (cm) is the measurement of length.

Delvig [45]3 years ago

5 0

Kg would signify as the measurement of weight
mL is for volume
Cm is for length/width

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What is the mass in grams of 4.85 x 1022 al atoms?

aliya0001 [1]

Based on the calculations, the mass of Aluminum in 4.85 × 10²² atoms is equal to 2.1762 grams.

<h3>How to calculate the mass of Aluminum?</h3>

In order to determine the mass of Aluminum, we would calculate the number of atoms in 1 mole of an Aluminum atom in accordance with Avogadro's constant.

1 mole of Aluminum atom = 6.02 × 10²³ molecules

X moles of Aluminum atom = 4.85 × 10²² molecules

Cross-multiplying, we have:

X = 4.85 × 10²²/6.02 × 10²³

X = 0.0806 moles.

Mass = Molar mass × Number of moles

Mass = 27 × 0.0806

Mass = 2.1762 grams.

Read more on moles here: brainly.com/question/3173452

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2 years ago

What is starchelement compound or mixture

adelina 88 [10]

Starch is a compound.

7 0

3 years ago

How many moles are in 16.0 grams of O2?

Naddika [18.5K]

1.0006 moles O2

To solve for moles to grams, you use the molar mass (from the periodic table, so for oxygen it is 15.999 grams) to solve for moles this you set up the equation like this:

6 0

3 years ago

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0

4 years ago

The solubility of nitrogen gas at 25°C and a nitrogen pressure of 522 mmHg is 4.7 × 10 –4 mol/L. What is the value of the Henry'

Anestetic [448]

Answer:

6.8 × 10⁻⁴ mol/L.atm

Explanation:

Step 1: Given data

Solubility of nitrogen gas at 25°C (S): 4.7 × 10⁻⁴ mol/L

Partial pressure of nitrogen gas (P): 522 mmHg

Step 2: Convert the partial pressure of nitrogen to atm

We will use the relationship 1 atm = 760 mmHg.

$522mmHg \times \frac{1atm}{760mmHg} = 0.687atm$

Step 3: Calculate the value of the Henry's Law constant (k)

We will use Henry's law.

$S = k \times P\\k = \frac{S}{P} = \frac{4.7 \times 10^{-4}mol/L }{0.687atm} = 6.8 \times 10^{-4} mol/L.atm$

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4 years ago