Question

Enter the condensed electron configuration for cu4+.express your answer in condensed form, in order of increasing orbital energy. for example [he]2s22p2, would be entered as [he]2s^22p^2.

Answer 1

Electronic Configuration of Cu⁴⁺ is written using these two steps;

Step I:
          Write the Electronic Configuration of Copper (Cu).

As Atomic Number of Cu = 29
So,
                             1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹

Rearranging it in order of increasing orbital energy,

                             1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
                            Cu  =   [Ar] 4s¹, 3d¹⁰

Step II:
            Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
                            Cu⁴⁺  =   [Ar] 3d⁷

Answer 2

Answer: The condensed electronic configuration of $Cu^{4+}$ is $[Ar]3d^7$

Explanation: Copper is an element belonging to the d-block of the periodic table. The atomic number of Cu-atom is 29.

Electronic configuration of Cu (Z=29) in the increasing order of the orbital energy = $1s^22s^22p^63s^23p^64s^13d^{10}$

Condensed electronic configuration of Cu is $[Ar]4s^13d^{10}$

Now, we need to write the electronic configuration of $Cu^{4+}$ ion, which becomes when 1 electron is released from 4s orbital and 3 electrons are released from 3d orbital. The configuration becomes:

$Cu^{4+}=[Ar]3d^7$